Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Which equation is the inverse of [tex]\( y = 7x^2 - 10 \)[/tex]?

A. [tex]\( y = \frac{ \pm \sqrt{x + 10}}{7} \)[/tex]
B. [tex]\( y = \pm \sqrt{\frac{x + 10}{7}} \)[/tex]
C. [tex]\( y = \pm \sqrt{\frac{x}{7} + 10} \)[/tex]
D. [tex]\( y = \frac{ \pm \sqrt{x}}{7} \pm \frac{\sqrt{10}}{7} \)[/tex]


Sagot :

To determine the inverse of the function [tex]\( y = 7x^2 - 10 \)[/tex], we follow these steps:

1. Start with the original function:
[tex]\[ y = 7x^2 - 10 \][/tex]

2. Swap the variables [tex]\( x \)[/tex] and [tex]\( y \)[/tex] to begin solving for the inverse:
[tex]\[ x = 7y^2 - 10 \][/tex]

3. Solve for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex]:
[tex]\[ x = 7y^2 - 10 \][/tex]

Add 10 to both sides:
[tex]\[ x + 10 = 7y^2 \][/tex]

Divide both sides by 7:
[tex]\[ \frac{x + 10}{7} = y^2 \][/tex]

4. Take the square root of both sides to solve for [tex]\( y \)[/tex]:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]

Thus, the inverse function of [tex]\( y = 7x^2 - 10 \)[/tex] is given by:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]

Therefore, the correct answer is:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.