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Sagot :
To determine the inverse of the function [tex]\( y = 7x^2 - 10 \)[/tex], we follow these steps:
1. Start with the original function:
[tex]\[ y = 7x^2 - 10 \][/tex]
2. Swap the variables [tex]\( x \)[/tex] and [tex]\( y \)[/tex] to begin solving for the inverse:
[tex]\[ x = 7y^2 - 10 \][/tex]
3. Solve for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex]:
[tex]\[ x = 7y^2 - 10 \][/tex]
Add 10 to both sides:
[tex]\[ x + 10 = 7y^2 \][/tex]
Divide both sides by 7:
[tex]\[ \frac{x + 10}{7} = y^2 \][/tex]
4. Take the square root of both sides to solve for [tex]\( y \)[/tex]:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
Thus, the inverse function of [tex]\( y = 7x^2 - 10 \)[/tex] is given by:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
Therefore, the correct answer is:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
1. Start with the original function:
[tex]\[ y = 7x^2 - 10 \][/tex]
2. Swap the variables [tex]\( x \)[/tex] and [tex]\( y \)[/tex] to begin solving for the inverse:
[tex]\[ x = 7y^2 - 10 \][/tex]
3. Solve for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex]:
[tex]\[ x = 7y^2 - 10 \][/tex]
Add 10 to both sides:
[tex]\[ x + 10 = 7y^2 \][/tex]
Divide both sides by 7:
[tex]\[ \frac{x + 10}{7} = y^2 \][/tex]
4. Take the square root of both sides to solve for [tex]\( y \)[/tex]:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
Thus, the inverse function of [tex]\( y = 7x^2 - 10 \)[/tex] is given by:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
Therefore, the correct answer is:
[tex]\[ y = \pm \sqrt{\frac{x + 10}{7}} \][/tex]
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