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Three positive whole numbers are all different. they have a median of 5 and a mean of 4. find the three numbers

Sagot :

Step-by-step explanation:

Solution:

Here,

Let three positive whole numbers which are all different be a,b and c

Given that the median is 5 i.e. b=5

It's also given that

Mean=4

So,

(a+b+c)/3=4

or, a+b+c=12

Since, b=5

By putting the value of b. We get

a+5+c=12

or,a+c=7

We need two different positive whole numbers that add up to 7. Since a < 5 and c > 5

If a = 2 then c = 7 - 2 = 5

This configuration does not work because cmust be greater than b. Let's try other combinations:

a = 3 then c = 7 - 3 = 4

This configuration also does not work because a is less than b, and b is not different.

If a = 2 then c = 7 - 2 = 5

c must be different from b

Now, let's Identify a valid configuration:

If a = 3 then c = 7 - 3 = 3

This does not work as 4is less than 5..

If a = 1 then c = 6

This configuration satisfies all conditions:

-(a < b < c)

- (a = 1), (b = 5), (c = 6)

- (a + b + c = 1 + 5 + 6 = 12)

Therefore, the three different positive whole numbers are 1,5 and 6

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