Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Step-by-step explanation:
Solution:
Here,
Let three positive whole numbers which are all different be a,b and c
Given that the median is 5 i.e. b=5
It's also given that
Mean=4
So,
(a+b+c)/3=4
or, a+b+c=12
Since, b=5
By putting the value of b. We get
a+5+c=12
or,a+c=7
We need two different positive whole numbers that add up to 7. Since a < 5 and c > 5
If a = 2 then c = 7 - 2 = 5
This configuration does not work because cmust be greater than b. Let's try other combinations:
a = 3 then c = 7 - 3 = 4
This configuration also does not work because a is less than b, and b is not different.
If a = 2 then c = 7 - 2 = 5
c must be different from b
Now, let's Identify a valid configuration:
If a = 3 then c = 7 - 3 = 3
This does not work as 4is less than 5..
If a = 1 then c = 6
This configuration satisfies all conditions:
-(a < b < c)
- (a = 1), (b = 5), (c = 6)
- (a + b + c = 1 + 5 + 6 = 12)
Therefore, the three different positive whole numbers are 1,5 and 6
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
