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Rewrite the log equation as an exponential equation. Do not solve for [tex]\( x \)[/tex].

[tex]\[ \log(3x + 9) = \frac{1}{3} \][/tex]

Answer:
[tex]\[ \square \][/tex]

Sagot :

GinnyAnswer
Certainly! Let's start with the given logarithmic equation:

[tex]\[ \log (3x + 9) = \frac{1}{3} \][/tex]

To convert this logarithmic equation into its exponential form, we need to understand that the logarithmic form [tex]\(\log_b(a) = c\)[/tex] is equivalent to the exponential form [tex]\(a = b^c\)[/tex]. Here, the base [tex]\(b\)[/tex] is 10, as it's implied when the base is not specified. Therefore, we can rewrite the equation as:

[tex]\[ 3x + 9 = 10^{\frac{1}{3}} \][/tex]

So, in exponential form, the equation is:

[tex]\[ 3x + 9 = 10^{\frac{1}{3}} \][/tex]

This is the exponential form of the given logarithmic equation.
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