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Sagot :
To analyze Jillana's linear equation, consider the following general form for a linear equation:
[tex]\[ ax + b = ax + b \][/tex]
Here, [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants, and [tex]\(x\)[/tex] is the variable.
When you simplify this equation, you'll subtract [tex]\(ax + b\)[/tex] from both sides:
[tex]\[ ax + b - (ax + b) = ax + b - (ax + b) \][/tex]
[tex]\[ 0 = 0 \][/tex]
The resulting statement [tex]\( 0 = 0 \)[/tex] is always true, independent of the value of [tex]\(x\)[/tex]. This means that any value for [tex]\(x\)[/tex] will satisfy the original equation.
Therefore, we interpret the equation as having infinitely many solutions, since every value for [tex]\(x\)[/tex] makes the equation true. The best interpretation of this situation is:
The equation has infinite solutions.
[tex]\[ ax + b = ax + b \][/tex]
Here, [tex]\( a \)[/tex] and [tex]\( b \)[/tex] are constants, and [tex]\(x\)[/tex] is the variable.
When you simplify this equation, you'll subtract [tex]\(ax + b\)[/tex] from both sides:
[tex]\[ ax + b - (ax + b) = ax + b - (ax + b) \][/tex]
[tex]\[ 0 = 0 \][/tex]
The resulting statement [tex]\( 0 = 0 \)[/tex] is always true, independent of the value of [tex]\(x\)[/tex]. This means that any value for [tex]\(x\)[/tex] will satisfy the original equation.
Therefore, we interpret the equation as having infinitely many solutions, since every value for [tex]\(x\)[/tex] makes the equation true. The best interpretation of this situation is:
The equation has infinite solutions.
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