Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
To determine how many liters would be occupied by 10.0 kg of wood with a density of 0.880 g/mL, follow these steps:
1. Convert the density to consistent units:
- Since we want the volume in liters and the mass is given in kilograms, we need to convert the density from g/mL to kg/L.
- Density Conversion: 1 g/mL is equivalent to 1,000 kg/L.
- Thus, 0.880 g/mL is equivalent to [tex]\( 0.880 \times 0.001 = 0.00088 \)[/tex] kg/L.
2. Use the formula for density:
- Density (ρ) is defined as mass (m) divided by volume (V). Hence, [tex]\( \rho = \frac{m}{V} \)[/tex].
- Rearrange the formula to solve for volume: [tex]\( V = \frac{m}{\rho} \)[/tex].
3. Plug in the given values:
- Mass (m) = 10.0 kg
- Density (ρ) = 0.00088 kg/L
4. Calculate the volume:
- Volume (V) = [tex]\( \frac{10.0 \text{ kg}}{0.00088 \text{ kg/L}} \)[/tex].
5. Perform the division:
- Volume (V) = 11,363.636363636364 liters.
Therefore, 10.0 kg of wood with a density of 0.880 g/mL would occupy approximately 11,363.64 liters.
1. Convert the density to consistent units:
- Since we want the volume in liters and the mass is given in kilograms, we need to convert the density from g/mL to kg/L.
- Density Conversion: 1 g/mL is equivalent to 1,000 kg/L.
- Thus, 0.880 g/mL is equivalent to [tex]\( 0.880 \times 0.001 = 0.00088 \)[/tex] kg/L.
2. Use the formula for density:
- Density (ρ) is defined as mass (m) divided by volume (V). Hence, [tex]\( \rho = \frac{m}{V} \)[/tex].
- Rearrange the formula to solve for volume: [tex]\( V = \frac{m}{\rho} \)[/tex].
3. Plug in the given values:
- Mass (m) = 10.0 kg
- Density (ρ) = 0.00088 kg/L
4. Calculate the volume:
- Volume (V) = [tex]\( \frac{10.0 \text{ kg}}{0.00088 \text{ kg/L}} \)[/tex].
5. Perform the division:
- Volume (V) = 11,363.636363636364 liters.
Therefore, 10.0 kg of wood with a density of 0.880 g/mL would occupy approximately 11,363.64 liters.
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.