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Select the correct statement about the function represented by the table.

[tex]\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
1 & 7 \\
\hline
2 & 21 \\
\hline
3 & 63 \\
\hline
4 & 189 \\
\hline
5 & 567 \\
\hline
\end{array}
\][/tex]

A. It is an exponential function because the [tex]$y$[/tex]-values increase by an equal factor over equal intervals of [tex]$x$[/tex]-values.
B. It is an exponential function because the factor between each [tex]$x$[/tex] and [tex]$y$[/tex]-value is constant.
C. It is a linear function because the difference between each [tex]$x$[/tex] and [tex]$y$[/tex]-value is constant.
D. It is a linear function because the [tex]$y$[/tex]-values increase by an equal difference over equal intervals of [tex]$x$[/tex]-values.

Sagot :

GinnyAnswer
To determine the correct statement about the function represented by the table, we need to analyze how the [tex]\( y \)[/tex]-values change relative to the [tex]\( x \)[/tex]-values.

First, let's look at the given data:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 7 \\ \hline 2 & 21 \\ \hline 3 & 63 \\ \hline 4 & 189 \\ \hline 5 & 567 \\ \hline \end{array} \][/tex]

Our goal is to determine whether the function is exponential or linear and find the correct reason.

#### Exponential Function Check

An exponential function has the property that the ratio between consecutive [tex]\( y \)[/tex]-values is constant. Let's calculate the ratio between consecutive [tex]\( y \)[/tex]-values:
- For [tex]\( x = 1 \)[/tex] and [tex]\( x = 2 \)[/tex]:
[tex]\[ \frac{21}{7} = 3 \][/tex]
- For [tex]\( x = 2 \)[/tex] and [tex]\( x = 3 \)[/tex]:
[tex]\[ \frac{63}{21} = 3 \][/tex]
- For [tex]\( x = 3 \)[/tex] and [tex]\( x = 4 \)[/tex]:
[tex]\[ \frac{189}{63} = 3 \][/tex]
- For [tex]\( x = 4 \)[/tex] and [tex]\( x = 5 \)[/tex]:
[tex]\[ \frac{567}{189} = 3 \][/tex]

Since the ratio [tex]\( \frac{y_{i+1}}{y_i} \)[/tex] is consistently 3 for all consecutive pairs of [tex]\( y \)[/tex]-values, the function is exponential.

#### Linear Function Check

A linear function has the property that the difference between consecutive [tex]\( y \)[/tex]-values is constant. Let's calculate the difference between consecutive [tex]\( y \)[/tex]-values:
- For [tex]\( x = 1 \)[/tex] and [tex]\( x = 2 \)[/tex]:
[tex]\[ 21 - 7 = 14 \][/tex]
- For [tex]\( x = 2 \)[/tex] and [tex]\( x = 3 \)[/tex]:
[tex]\[ 63 - 21 = 42 \][/tex]
- For [tex]\( x = 3 \)[/tex] and [tex]\( x = 4 \)[/tex]:
[tex]\[ 189 - 63 = 126 \][/tex]
- For [tex]\( x = 4 \)[/tex] and [tex]\( x = 5 \)[/tex]:
[tex]\[ 567 - 189 = 378 \][/tex]

Since the differences [tex]\( y_{i+1} - y_i \)[/tex] are not constant, the function is not linear.

Based on this analysis, we can determine the correct statement. The [tex]\( y \)[/tex]-values increase by an equal factor (3) over equal intervals of [tex]\( x \)[/tex]-values, which is a characteristic of an exponential function.

Hence, the correct answer is:
A. It is an exponential function because the [tex]\( y \)[/tex]-values increase by an equal factor over equal intervals of [tex]\( x \)[/tex]-values.
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