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What move can we make to get rid of [tex]\(-5h\)[/tex] on the left so that all the [tex]\(h\)[/tex] terms are on the right, while maintaining balance?

[tex]\[
\begin{aligned}
12-5(h+2) & = 3h - 10 \\
12-5h-10 & = 3h - 10 \\
-5h + 2 & = 3h - 10
\end{aligned}
\][/tex]

A. Add [tex]\(5h\)[/tex] to both sides
B. Subtract [tex]\(5h\)[/tex] from both sides
C. Multiply both sides by [tex]\(5h\)[/tex]
D. Divide both sides by [tex]\(5h\)[/tex]

Sagot :

GinnyAnswer
To get rid of [tex]\(-5h\)[/tex] on the left side and put all the [tex]\(h\)[/tex] terms on the right side while maintaining balance, we need to add [tex]\(5h\)[/tex] to both sides. Here's the detailed step-by-step solution:

We start with the equation:
[tex]\[ -5h + 2 = 3h - 10 \][/tex]

To get rid of [tex]\(-5h\)[/tex] on the left side, we need to add [tex]\(5h\)[/tex] to both sides. This will move all the [tex]\(h\)[/tex] terms to the right side of the equation.

Add [tex]\(5h\)[/tex] to both sides:
[tex]\[ -5h + 2 + 5h = 3h - 10 + 5h \][/tex]

Simplify both sides:
[tex]\[ 2 = 8h - 10 \][/tex]

Now, all the [tex]\(h\)[/tex] terms are on the right side. This completes the step of moving the [tex]\(h\)[/tex] terms to the right while maintaining balance.

So, the correct move is to add [tex]\(5h\)[/tex] to both sides.
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