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Expand the following expression:
[tex]\[
\ln\left(\frac{5x^2y^4}{w^3}\right)
\][/tex]

A. [tex]\(\ln(5) + 2 \cdot \ln(x) + 4 \cdot \ln(y) - 3 \cdot \ln(w)\)[/tex]

B. [tex]\(\ln(5) + 2 \cdot \ln(x) - 4 \cdot \ln(y) - 3 \cdot \ln(w)\)[/tex]

C. [tex]\(\ln(5) - 2 \cdot \ln(x) - 4 \cdot \ln(y) - 3 \cdot \ln(w)\)[/tex]

D. [tex]\(\ln(5) + 2 \cdot \ln(x) + 4 \cdot \ln(y) + 3 \cdot \ln(w)\)[/tex]


Sagot :

To expand the logarithmic expression [tex]\(\ln\left(\frac{5 x^2 y^4}{w^3}\right)\)[/tex], we can use the properties of logarithms. Specifically, we'll apply the following logarithmic properties:

1. [tex]\(\ln(ab) = \ln(a) + \ln(b)\)[/tex]
2. [tex]\(\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\)[/tex]
3. [tex]\(\ln(a^n) = n \cdot \ln(a)\)[/tex]

Given the expression [tex]\(\ln\left(\frac{5 x^2 y^4}{w^3}\right)\)[/tex]:

1. Apply the logarithmic property for division, [tex]\(\ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b)\)[/tex]:

[tex]\[ \ln\left(\frac{5 x^2 y^4}{w^3}\right) = \ln\left(5 x^2 y^4\right) - \ln(w^3) \][/tex]

2. Apply the logarithmic property for multiplication, [tex]\(\ln(ab) = \ln(a) + \ln(b)\)[/tex], to [tex]\(\ln\left(5 x^2 y^4\right)\)[/tex]:

[tex]\[ \ln\left(5 x^2 y^4\right) = \ln(5) + \ln(x^2) + \ln(y^4) \][/tex]

3. Apply the logarithmic property for exponentiation, [tex]\(\ln(a^n) = n \cdot \ln(a)\)[/tex]:

[tex]\[ \ln(x^2) = 2 \cdot \ln(x) \quad \text{and} \quad \ln(y^4) = 4 \cdot \ln(y) \][/tex]

Thus,

[tex]\[ \ln\left(5 x^2 y^4\right) = \ln(5) + 2 \cdot \ln(x) + 4 \cdot \ln(y) \][/tex]

4. Apply the logarithmic property for exponentiation to [tex]\(\ln(w^3)\)[/tex]:

[tex]\[ \ln(w^3) = 3 \cdot \ln(w) \][/tex]

5. Combine everything:

[tex]\[ \ln\left(\frac{5 x^2 y^4}{w^3}\right) = \ln(5) + 2 \cdot \ln(x) + 4 \cdot \ln(y) - 3 \cdot \ln(w) \][/tex]

Therefore, the expanded expression is:

[tex]\[ \ln(5) + 2 \cdot \ln(x) + 4 \cdot \ln(y) - 3 \cdot \ln(w) \][/tex]

Which corresponds to the first answer option:

[tex]\[ \ln (5)+2 \cdot \ln (x)+4 \cdot \ln (y)-3 \cdot \ln (w) \][/tex]