Answered

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Type the program's output:

```python
g = 0
while g <= 3:
print(g)
g += 1
```

Output:
```plaintext
0
1
2
3
```

Sagot :

GinnyAnswer
Let's solve the problem step-by-step:

We start with the variable [tex]\( g \)[/tex] initialized to 0.

1. First Iteration:
- Condition Check: [tex]\( g \leq 3 \)[/tex] (since [tex]\( g = 0 \)[/tex])
- Print Value: 0
- Increment: [tex]\( g \)[/tex] becomes 1 (0 + 1)

2. Second Iteration:
- Condition Check: [tex]\( g \leq 3 \)[/tex] (since [tex]\( g = 1 \)[/tex])
- Print Value: 1
- Increment: [tex]\( g \)[/tex] becomes 2 (1 + 1)

3. Third Iteration:
- Condition Check: [tex]\( g \leq 3 \)[/tex] (since [tex]\( g = 2 \)[/tex])
- Print Value: 2
- Increment: [tex]\( g \)[/tex] becomes 3 (2 + 1)

4. Fourth Iteration:
- Condition Check: [tex]\( g \leq 3 \)[/tex] (since [tex]\( g = 3 \)[/tex])
- Print Value: 3
- Increment: [tex]\( g \)[/tex] becomes 4 (3 + 1)

5. Fifth Iteration:
- Condition Check: [tex]\( g \leq 3 \)[/tex] (Again, since [tex]\( g = 4 \)[/tex] now, the condition fails)
- The loop stops here.

The output after running through these iterations is:
[tex]\[ [0, 1, 2, 3] \][/tex]

Thus, the program outputs the numbers [tex]\( 0, 1, 2, \)[/tex] and [tex]\( 3 \)[/tex].
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