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he graph of a line goes through the points (-4,3) and (6,8). What is the equation of the line in slope-intercept form?

Sagot :

Answer:

[tex]y=\dfrac{1}{2}x+5[/tex]

Step-by-step explanation:

Slope - Intercept Form

Linear functions and equations can be written in slope-intercept form which is the formal name of y = mx + b, where m is the slope and b is the y-intercept of the line.

To find m using 2 points on the line, we use this formula:

                                                   [tex]\dfrac{y_2-y_1}{x_2-x_1}[/tex],

where the subscripts 1 and 2 indicates which coordinate pair the value originates from.

If we're given a solution to the line then we can plug its x and y value into the equation and rearrange to find the b value.

Solving the Problem

We're given two points, so we plug them into the slope formula.

Let [tex](x_2,y_2)=(6,8)[/tex] and [tex](x_1,y-1)=(-4,3)[/tex],

                                      [tex]\dfrac{8-3}{6-(-4)} =\dfrac{5}{10} =\dfrac{1}{2}[/tex].

Plugging the m value into the slope-intercept format we have,

                                             [tex]y=\dfrac{1}{2}x+b[/tex].

Now we can plug either (-4,3) or (6,8), we'll plug in (6,8) for simplicity.

                                           [tex]8=\dfrac{1}{2}(6)+b\\\\[/tex]

                                             [tex]8=3+b\\\Longrightarrow 5 = b[/tex]

So, the equation of the line is [tex]y=\dfrac{1}{2}x+5[/tex].

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