Sure, let's solve these equations step-by-step using inverse operations.
### 1) [tex]\( x + 5 = 20 \)[/tex]
To solve for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex] on one side of the equation. We can do this by performing the inverse operation of addition, which is subtraction.
Subtract 5 from both sides of the equation:
[tex]\[
x + 5 - 5 = 20 - 5
\][/tex]
Simplify both sides:
[tex]\[
x = 15
\][/tex]
So, [tex]\( x = 15 \)[/tex].
### 2) [tex]\( 15.45 = b + 3.1 \)[/tex]
To solve for [tex]\( b \)[/tex], we again need to isolate [tex]\( b \)[/tex] on one side of the equation. This time, we perform the inverse operation of addition, which is subtraction.
Subtract 3.1 from both sides of the equation:
[tex]\[
15.45 - 3.1 = b + 3.1 - 3.1
\][/tex]
Simplify both sides:
[tex]\[
12.35 = b
\][/tex]
So, [tex]\( b = 12.35 \)[/tex].
### 3) [tex]\( a - 8 = -11 \)[/tex]
To solve for [tex]\( a \)[/tex], we need to isolate [tex]\( a \)[/tex] on one side of the equation. This time, we perform the inverse operation of subtraction, which is addition.
Add 8 to both sides of the equation:
[tex]\[
a - 8 + 8 = -11 + 8
\][/tex]
Simplify both sides:
[tex]\[
a = -3
\][/tex]
So, [tex]\( a = -3 \)[/tex].
In summary:
1. [tex]\( x = 15 \)[/tex]
2. [tex]\( b = 12.35 \)[/tex]
3. [tex]\( a = -3 \)[/tex]
