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What is the general equation of a sine function with an amplitude of 6, a period of [tex]\(\frac{\pi}{4}\)[/tex], and a horizontal shift of [tex]\(\frac{\pi}{2}\)[/tex]?

A. [tex]\(y = \sin \left(8\left(x-\frac{\pi}{2}\right)\right)\)[/tex]

B. [tex]\(y = 8 \sin \left(4\left(x-\frac{\pi}{2}\right)\right)\)[/tex]

C. [tex]\(y = 6 \sin \left(8\left(x-\frac{\pi}{2}\right)\right)\)[/tex]

D. [tex]\(y = 6 \sin (8x) + \frac{\pi}{2}\)[/tex]


Sagot :

To find the general equation of a sine function given the amplitude, period, and horizontal shift, we follow these steps:

1. Amplitude (A): The coefficient in front of the sine function represents the amplitude. Given that the amplitude is 6, this directly translates to the function being multiplied by 6.

2. Period (T): The period of a sine function is given by the formula [tex]\( T = \frac{2\pi}{B} \)[/tex], where [tex]\( B \)[/tex] is the coefficient of [tex]\( x \)[/tex] inside the sine function. Given that the period is [tex]\( \frac{\pi}{4} \)[/tex], we can substitute this value into the formula and solve for [tex]\( B \)[/tex]:
[tex]\[ \frac{2\pi}{B} = \frac{\pi}{4} \][/tex]
To find [tex]\( B \)[/tex], multiply both sides of the equation by [tex]\( B \)[/tex]:
[tex]\[ 2\pi = B \cdot \frac{\pi}{4} \][/tex]
Now, solve for [tex]\( B \)[/tex] by isolating it:
[tex]\[ B = \frac{2\pi}{\pi/4} = 8 \][/tex]

3. Horizontal Shift (C): The horizontal shift is given directly and is represented within the sine function as [tex]\( x - C \)[/tex]. Given that the horizontal shift is [tex]\( \frac{\pi}{2} \)[/tex], it appears in the equation as [tex]\( x - \frac{\pi}{2} \)[/tex].

Putting these values together into the general form of the sine function [tex]\( y = A \sin(B(x - C)) \)[/tex], we get:
[tex]\[ y = 6 \sin(8(x - \frac{\pi}{2})) \][/tex]

Therefore, the correct equation for the sine function with the given parameters is:
[tex]\[ y = 6 \sin (8 (x - \frac{\pi}{2})) \][/tex]

So the correct answer is:
[tex]\[ y = 6 \sin \left(8 \left(x - \frac{\pi}{2}\right)\right) \][/tex]