Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Sure, let's analyze each of the given chemical equations step-by-step to determine which ones are unbalanced.
### Equation 1:
[tex]\[ C + O_2 \rightarrow CO_2 \][/tex]
To check the balance of this equation, we will count the number of atoms of each element on both sides of the equation.
Left side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms (in [tex]\(CO_2\)[/tex])
Both sides have:
- 1 Carbon
- 2 Oxygen
Therefore, [tex]\(C + O_2 \rightarrow CO_2\)[/tex] is balanced.
### Equation 2:
[tex]\[ Sr + O_2 \rightarrow 2 SrO \][/tex]
Left side:
- Strontium (Sr): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Strontium (Sr): 2 atoms (in [tex]\(2 SrO\)[/tex])
- Oxygen (O): 2 atoms (in [tex]\(2 SrO\)[/tex])
The left side has:
- 1 Strontium
- 2 Oxygen
The right side has:
- 2 Strontium
- 2 Oxygen
Therefore, [tex]\(Sr + O_2 \rightarrow 2 SrO\)[/tex] is unbalanced because the number of Strontium atoms on both sides doesn't match.
### Equation 3:
[tex]\[ 6 H_2 + 3 O_2 \rightarrow 6 H_2O \][/tex]
Left side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms
- Oxygen (O): [tex]\(3 \times 2 = 6\)[/tex] atoms
Right side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
- Oxygen (O): [tex]\(6 \times 1 = 6\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
Both sides have:
- 12 Hydrogen
- 6 Oxygen
Therefore, [tex]\(6 H_2 + 3 O_2 \rightarrow 6 H_2O\)[/tex] is balanced.
### Equation 4:
[tex]\[ H_2 + H_2 + O_2 \rightarrow H_2O + H_2O \][/tex]
We can combine the terms on the left-hand side for simplification:
[tex]\[ 2 H_2 + O_2 \rightarrow 2 H_2O \][/tex]
Now, let's count the atoms:
Left side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms
- Oxygen (O): 2 atoms
Right side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
- Oxygen (O): [tex]\(2 \times 1 = 2\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
Both sides have:
- 4 Hydrogen
- 2 Oxygen
Therefore, [tex]\(2 H_2 + O_2 \rightarrow 2 H_2O\)[/tex] is balanced.
### Conclusion:
After examining each equation, we find that the equations which are unbalanced are:
1. [tex]\( Sr + O_2 \rightarrow 2 SrO\)[/tex]
So, the unbalanced equations are:
[tex]\[ 1, 2, 3, 4\][/tex]
### Equation 1:
[tex]\[ C + O_2 \rightarrow CO_2 \][/tex]
To check the balance of this equation, we will count the number of atoms of each element on both sides of the equation.
Left side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Carbon (C): 1 atom
- Oxygen (O): 2 atoms (in [tex]\(CO_2\)[/tex])
Both sides have:
- 1 Carbon
- 2 Oxygen
Therefore, [tex]\(C + O_2 \rightarrow CO_2\)[/tex] is balanced.
### Equation 2:
[tex]\[ Sr + O_2 \rightarrow 2 SrO \][/tex]
Left side:
- Strontium (Sr): 1 atom
- Oxygen (O): 2 atoms
Right side:
- Strontium (Sr): 2 atoms (in [tex]\(2 SrO\)[/tex])
- Oxygen (O): 2 atoms (in [tex]\(2 SrO\)[/tex])
The left side has:
- 1 Strontium
- 2 Oxygen
The right side has:
- 2 Strontium
- 2 Oxygen
Therefore, [tex]\(Sr + O_2 \rightarrow 2 SrO\)[/tex] is unbalanced because the number of Strontium atoms on both sides doesn't match.
### Equation 3:
[tex]\[ 6 H_2 + 3 O_2 \rightarrow 6 H_2O \][/tex]
Left side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms
- Oxygen (O): [tex]\(3 \times 2 = 6\)[/tex] atoms
Right side:
- Hydrogen (H): [tex]\(6 \times 2 = 12\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
- Oxygen (O): [tex]\(6 \times 1 = 6\)[/tex] atoms (in [tex]\(6 H_2O\)[/tex])
Both sides have:
- 12 Hydrogen
- 6 Oxygen
Therefore, [tex]\(6 H_2 + 3 O_2 \rightarrow 6 H_2O\)[/tex] is balanced.
### Equation 4:
[tex]\[ H_2 + H_2 + O_2 \rightarrow H_2O + H_2O \][/tex]
We can combine the terms on the left-hand side for simplification:
[tex]\[ 2 H_2 + O_2 \rightarrow 2 H_2O \][/tex]
Now, let's count the atoms:
Left side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms
- Oxygen (O): 2 atoms
Right side:
- Hydrogen (H): [tex]\(2 \times 2 = 4\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
- Oxygen (O): [tex]\(2 \times 1 = 2\)[/tex] atoms (in [tex]\(2 H_2O\)[/tex])
Both sides have:
- 4 Hydrogen
- 2 Oxygen
Therefore, [tex]\(2 H_2 + O_2 \rightarrow 2 H_2O\)[/tex] is balanced.
### Conclusion:
After examining each equation, we find that the equations which are unbalanced are:
1. [tex]\( Sr + O_2 \rightarrow 2 SrO\)[/tex]
So, the unbalanced equations are:
[tex]\[ 1, 2, 3, 4\][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
