Answered

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Considering the activity series below for metals and nonmetals:

Al > Mn > Zn > Cr > Fe > Cd > Co > Ni > Sn > Pb > H > Sb > Bi > Cu > Ag > Pd > Hg > Pt > Cl > Br > I

Determine whether each of the following reactions will occur:

1. [tex]\(2 \text{NaBr} + \text{I}_2 \rightarrow 2 \text{NaI} + \text{Br}_2\)[/tex]
2. [tex]\(2 \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{Al} + \text{Fe}_2\text{O}_3\)[/tex]
3. [tex]\(2 \text{AgNO}_3 + \text{Ni} \rightarrow \text{Ni(NO}_3\text{)}_2 + 2 \text{Ag}\)[/tex]
4. [tex]\(\text{Pb} + \text{Zn(C}_2\text{H}_3\text{O}_2\text{)}_2 \rightarrow \text{Zn} + \text{Pb(C}_2\text{H}_3\text{O}_2\text{)}_2\)[/tex]

Sagot :

GinnyAnswer
To determine the feasibility of the given reactions based on the activity series, we need to compare the reactivity of the elements involved:

1. Reaction 1: [tex]\( 2 \text{NaBr} + I_2 \rightarrow 2 \text{NaI} + Br_2 \)[/tex]

- Question: Can [tex]\( I_2 \)[/tex] displace [tex]\( Br^- \)[/tex] from [tex]\( \text{NaBr} \)[/tex]?
- Activity Series: [tex]\[ >Cl > Br > I \][/tex]
- Explanation: Since bromine (Br) is more reactive than iodine (I), iodine cannot displace bromine from sodium bromide (NaBr).

Thus, Reaction 1 is not feasible.

2. Reaction 2: [tex]\( 2 \text{Fe} + \text{Al}_2\text{O}_3 \rightarrow 2 \text{Al} + \text{Fe}_2\text{O}_3 \)[/tex]

- Question: Can iron (Fe) displace aluminum (Al) from aluminum oxide ([tex]\( \text{Al}_2\text{O}_3 \)[/tex])?
- Activity Series: [tex]\[ Al > Mn > Zn > Cr > Fe \][/tex]
- Explanation: Since aluminum (Al) is more reactive than iron (Fe), iron cannot displace aluminum from aluminum oxide.

Thus, Reaction 2 is not feasible.

3. Reaction 3: [tex]\( 2 \text{AgNO}_3 + \text{Ni} \rightarrow \text{Ni}(\text{NO}_3)_2 + 2 \text{Ag} \)[/tex]

- Question: Can nickel (Ni) displace silver (Ag) from silver nitrate ([tex]\( \text{AgNO}_3 \)[/tex])?
- Activity Series: [tex]\[ Ni > Sn > Pb > H > Sb > Bi > Cu > Ag \][/tex]
- Explanation: Since nickel (Ni) is more reactive than silver (Ag), nickel can displace silver from silver nitrate.

Thus, Reaction 3 is feasible.

4. Reaction 4: [tex]\( \text{Pb} + \text{Zn}(\text{C}_2\text{H}_3\text{O}_2)_2 \rightarrow \text{Zn} + \text{Pb}(\text{C}_2\text{H}_3\text{O}_2)_2 \)[/tex]

- Question: Can lead (Pb) displace zinc (Zn) from zinc acetate ([tex]\( \text{Zn}(\text{C}_2\text{H}_3\text{O}_2)_2 \)[/tex])?
- Activity Series: [tex]\[ Zn > Sn > Pb \][/tex]
- Explanation: Since zinc (Zn) is more reactive than lead (Pb), lead cannot displace zinc from zinc acetate.

Thus, Reaction 4 is not feasible.

Summary:
- Reaction 1: Not feasible (False)
- Reaction 2: Not feasible (False)
- Reaction 3: Feasible (True)
- Reaction 4: Not feasible (False)

The resulting outcomes for the feasibility of the reactions are: [tex]\( \boxed{(False, False, True, False)} \)[/tex].
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