Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A total of [tex]$300,000 in school funds is to be distributed to four middle schools using proportional apportionment. The number of kids in each school is shown in the table below.

| School | Number of Kids |
|---------------|----------------|
| North Middle | 400 |
| South Middle | 650 |
| East Middle | 500 |
| West Middle | 450 |

How much of the funding should go to North Middle?

A. $[/tex]67,500
B. [tex]$60,000
C. $[/tex]75,000
D. $97,500


Sagot :

Let's determine how much of the \[tex]$300,000 in school funds should go to North Middle. We will distribute the funds proportionally based on the number of kids in each school. 1. Calculate the total number of kids across all four schools: We add up the number of kids in each school: \[ 400 + 650 + 500 + 450 = 2000 \] 2. Determine the proportion of kids at North Middle relative to the total number of kids: The proportion is calculated by dividing the number of kids at North Middle by the total number of kids: \[ \text{Proportion of kids at North Middle} = \frac{400}{2000} = 0.2 \] 3. Calculate the funding for North Middle based on the proportion: We allocate the funds proportionally by multiplying the total funds by the proportion of kids at North Middle: \[ \text{Funding for North Middle} = 0.2 \times 300,000 = 60,000 \] Hence, the amount of funding that should go to North Middle is: \[ \boxed{60,000} \] Therefore, the correct answer is (B) \$[/tex]60,000.