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A puppy weighing 3 kilograms races through the dog park. If she slows from a speed of 2 meters/second to 1 meter/second, what will happen to her kinetic energy? Use the kinetic energy equation [tex]\( KE = \frac{1}{2} mv^2 \)[/tex].

A. Her kinetic energy decreases to [tex]\(1.5 \, J\)[/tex].
B. Her kinetic energy increases to [tex]\(1.5 \, J\)[/tex].
C. Her kinetic energy remains unchanged.
D. Her kinetic energy decreases to [tex]\(1 \, J\)[/tex].

Sagot :

To determine what will happen to the puppy's kinetic energy as she slows down, we need to use the kinetic energy equation:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]

Here, [tex]\( m \)[/tex] is the mass of the puppy, and [tex]\( v \)[/tex] is the velocity. Let's follow the steps to calculate her initial and final kinetic energy:

1. Given Values:
- Mass ([tex]\( m \)[/tex]) of the puppy: 3 kilograms
- Initial speed ([tex]\( v_i \)[/tex]): 2 meters/second
- Final speed ([tex]\( v_f \)[/tex]): 1 meter/second

2. Calculate Initial Kinetic Energy:
[tex]\[ KE_{\text{initial}} = \frac{1}{2} \times 3 \, \text{kg} \times (2 \, \text{m/s})^2 \][/tex]
[tex]\[ KE_{\text{initial}} = \frac{1}{2} \times 3 \times 4 \][/tex]
[tex]\[ KE_{\text{initial}} = \frac{1}{2} \times 12 \][/tex]
[tex]\[ KE_{\text{initial}} = 6 \, \text{Joules (J)} \][/tex]

3. Calculate Final Kinetic Energy:
[tex]\[ KE_{\text{final}} = \frac{1}{2} \times 3 \, \text{kg} \times (1 \, \text{m/s})^2 \][/tex]
[tex]\[ KE_{\text{final}} = \frac{1}{2} \times 3 \times 1 \][/tex]
[tex]\[ KE_{\text{final}} = \frac{1}{2} \times 3 \][/tex]
[tex]\[ KE_{\text{final}} = 1.5 \, \text{J} \][/tex]

Based on these calculations:

- The initial kinetic energy is 6 J.
- The final kinetic energy is 1.5 J.

The puppy's kinetic energy has decreased from 6 J to 1.5 J.

Thus, the correct answer is:
A. Her kinetic energy decreases to [tex]\(1.5 \, \text{J}\)[/tex].
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