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Phillip sells silver chains (s) for [tex]$18 each and gold chains (g) for $[/tex]42 each. Phillip wants to sell more than $300 worth of silver and gold chains.

Which inequality represents how many silver and gold chains Phillip must sell?

A. [tex]\(18s + 42g \ \textgreater \ 300\)[/tex]

B. [tex]\(18s + 42g \ \textless \ 300\)[/tex]

C. [tex]\(18s + 42g \geq 300\)[/tex]

D. [tex]\(18s + 42g \leq 300\)[/tex]

Sagot :

GinnyAnswer
To determine the inequality that represents how many silver chains (s) and gold chains (g) Phillip must sell to make more than \[tex]$300, let's break down the problem step-by-step. 1. Identify the individual prices of the items: - Phillip sells each silver chain for \$[/tex]18.
- Phillip sells each gold chain for \[tex]$42. 2. Formulate the expression for the total sales value: - The total revenue from selling \( s \) silver chains is \( 18s \) dollars. - The total revenue from selling \( g \) gold chains is \( 42g \) dollars. 3. Combine the expressions: - The combined revenue from selling both silver chains and gold chains can be expressed as \( 18s + 42g \). 4. Compare the combined revenue to the desired amount: - Phillip wants to sell more than \$[/tex]300 worth of chains. So, we need to set this total revenue greater than 300.

5. Construct the inequality:
- The inequality will be [tex]\( 18s + 42g > 300 \)[/tex].

So, combining all the steps together, we conclude that the inequality representing how many silver chains and gold chains Phillip must sell to exceed \$300 in sales is:

[tex]\[ 18s + 42g > 300 \][/tex]

Therefore, the correct inequality is:

1. [tex]\( 18s + 42g > 300 \)[/tex].
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