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Jim's sock drawer has two pairs of black socks, three pairs of white socks, one pair of green socks, and two pairs of gray socks. One evening he randomly picks three socks and ends up with 1 black, 1 white, and 1 gray sock. Without putting back the socks he picked, he picks another sock randomly. What is the probability that he will have a complete pair?

A. [tex]$\frac{2}{18}$[/tex]
B. [tex]$\frac{11}{13}$[/tex]
C. [tex]$\frac{1}{18}$[/tex]
D. [tex]$\frac{1}{18}$[/tex]


Sagot :

To determine the probability that Jim will complete a pair after picking a fourth sock, let's go through the solution step by step:

1. Initial Pairs of Socks:
- Black socks: 2 pairs (4 socks)
- White socks: 3 pairs (6 socks)
- Green socks: 1 pair (2 socks)
- Gray socks: 2 pairs (4 socks)

Therefore, the total number of socks is:
[tex]\[ (2 + 3 + 1 + 2) \times 2 = 16 \text{ socks} \][/tex]

2. Socks Picked Initially:
Jim picks 1 black, 1 white, and 1 gray sock.

3. Remaining Socks:
- Remaining black socks: [tex]\(4 - 1 = 3\)[/tex]
- Remaining white socks: [tex]\(6 - 1 = 5\)[/tex]
- Remaining green socks: [tex]\(2 \text{ (untouched)}\)[/tex]
- Remaining gray socks: [tex]\(4 - 1 = 3\)[/tex]

Now, the total remaining socks are:
[tex]\[ 3 + 5 + 2 + 3 = 13 \text{ socks} \][/tex]

4. Favorable Cases:
To complete a pair, he must pick another black, white, or gray sock. Therefore, the number of favorable cases (remaining socks of each color initially picked) is:
[tex]\[ 3 \text{ (black)} + 5 \text{ (white)} + 3 \text{ (gray)} = 11 \text{ socks} \][/tex]

5. Probability Calculation:
The probability of picking a sock that completes a pair is the number of favorable cases divided by the total number of remaining socks:
[tex]\[ \frac{11}{13} \][/tex]

Therefore, the probability that Jim will have a complete pair after picking the fourth sock is [tex]\( \frac{11}{13} \)[/tex], which matches option B.

So, the correct answer is:
[tex]\[ \boxed{\frac{11}{13}} \][/tex]