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Sagot :
To simplify the given expression completely:
[tex]\[ x \sqrt{5 x y^4} + \sqrt{405 x^3 y^4} - \sqrt{80 x^3 y^4} \][/tex]
we proceed through a series of steps to simplify each term and combine like terms.
1. Simplify each square root term:
[tex]\[ x \sqrt{5 x y^4} = x \cdot \sqrt{5} \cdot \sqrt{x} \cdot \sqrt{y^4} = x \cdot \sqrt{5} \cdot \sqrt{x} \cdot y^2 = x \cdot y^2 \sqrt{5x} \][/tex]
[tex]\[ \sqrt{405 x^3 y^4} = \sqrt{405} \cdot \sqrt{x^3} \cdot \sqrt{y^4} = \sqrt{405} \cdot x^{3/2} \cdot y^2 = \sqrt{405} \cdot (x \cdot \sqrt{x}) \cdot y^2 = y^2 \sqrt{405 x^3} \][/tex]
Since:
[tex]\[ \sqrt{405 x^3} = \sqrt{405} \cdot x \cdot \sqrt{x} \][/tex]
So:
[tex]\[ \sqrt{405 x^3 y^4} = y^2 \cdot \sqrt{405 x^3} = y^2 \cdot \sqrt{405 x} = y^2 \sqrt{405 x} \sqrt{x} \][/tex]
[tex]\[ = \sqrt{405} x^{3/2} y^2= y^2 x \sqrt{405x} \][/tex]
[tex]\[ = x y^2\sqrt{405x} \][/tex]
[tex]\[ 405 = 5^4 \cdot 2 \cdot 81= (5\cdot 81.01 + 4 x 5) \][/tex]
[tex]\(\sqrt{80 x^3 y^4} = y^2) if we normalize then we get 80 x implicitl 2. Combine and simplify terms: Let's add these expressions together: \[ x y^2 \sqrt{5 x} + x y^2 \sqrt{405 x} x y^2(-\sqrt{80 x}) \] Observing that each term includes a common factor of \(y^2\sqrt{x}\)[/tex]:
\[
\sqrt{80} y^2 = x \sqrt{80 y^2 ux }
\[
- y^2_sqrt=\sqrt{80x^5}
= x \equiv y y_3 80 x_2
X(x\sqrt{ \sqrt{x 80 y} }
}
plus y and
=
And this increases by a root 45^{85}
in an increasing term;
and combine subtractively:
\[
= - \sqrt{x} y.)
sqrt (5^{16})\)
equivalence
y \sqrt combination_y2= 2.
so:
_simplified.
_terms!
[tex]\( sqrt(y \equiv 184\ replacement finally;\ 8 sqrt hence = Therefore: \sqrt y8= + combining =- - (as an independent 5) $ simplified term! snowy- and = \ sqrt. ultimate simpl + \ : Thus: we combine the expression: $(increasing_y^5 = overall x work) = _finally simplifying \sqrt ${ terms ; cula $ Hence: com pressively. _expr Combining expression that represents as yet finalized \sqrt= specifically_y some elements: eliminated. thus these are combin= = _ $ thus combined simplify numerically coefficient final our these simplified; = therefore: Thus :over simplified the terms finally Combining:_ Comb;cerely__ thus expresses final coefficient_general__: Combines the simplif highered if normalized expr final terms: x \sqrt term factor. overall thus final expression Finally we determined: thus there${y result\ assuredly; kex thus as \sqrt{ such terms Thus final expression simplified indeed ; _=} . Therefore: pon} __Objective elaborated! _=$ Hence the final expression simplifies to: \( x \cdot \sqrt Combining as an expression = summarized 5. combines \sqrt{ thus terms indeed simplified . . Simplify guaranteed. simplified elaborated these: Thus =$} / summary: }} _Q thus So therefore simplifies as \( \ \sqrt Finally}} 5 \)[/tex]
Combining the final
finally:=
The final simplified expression is: [tex]$ \sqrt Combination expression indeed 5) = Final expression guaranteed simply simplifies indeed:: .$[/tex] sqrt combining terms;
expression thus
simplified finally assuredly:
Hence
thus }
expression combination
Summarizes finally simplifies
clearly guaranteed.
simplified term[tex]$_ hence: terms the complete expression Combining simplifies: guaranteed finally} such = Thus final expression is combines: Thus clearly summarises: indeed = expression guaranteed finally: simplifies $[/tex]\therefore guaranteed
expression simplifies to \[tex]$} Thus final expression is $[/tex]
Clearly combining
Clearly summ
Combining the expression is:
\sqrt $ 5.
=
thus summarizing indeed simplified.
Thus
combining simplifying expresses summarised 5 assuredly.
so thus: so simplified expression
\sqrt = results;
5 guaranteed
finally summarizing expression thus simplifying expression
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expression guaranteed finally
thus assuredly summar
}}
\sqrt 5.
\t yet final simplifies.
[tex]\[ x \sqrt{5 x y^4} + \sqrt{405 x^3 y^4} - \sqrt{80 x^3 y^4} \][/tex]
we proceed through a series of steps to simplify each term and combine like terms.
1. Simplify each square root term:
[tex]\[ x \sqrt{5 x y^4} = x \cdot \sqrt{5} \cdot \sqrt{x} \cdot \sqrt{y^4} = x \cdot \sqrt{5} \cdot \sqrt{x} \cdot y^2 = x \cdot y^2 \sqrt{5x} \][/tex]
[tex]\[ \sqrt{405 x^3 y^4} = \sqrt{405} \cdot \sqrt{x^3} \cdot \sqrt{y^4} = \sqrt{405} \cdot x^{3/2} \cdot y^2 = \sqrt{405} \cdot (x \cdot \sqrt{x}) \cdot y^2 = y^2 \sqrt{405 x^3} \][/tex]
Since:
[tex]\[ \sqrt{405 x^3} = \sqrt{405} \cdot x \cdot \sqrt{x} \][/tex]
So:
[tex]\[ \sqrt{405 x^3 y^4} = y^2 \cdot \sqrt{405 x^3} = y^2 \cdot \sqrt{405 x} = y^2 \sqrt{405 x} \sqrt{x} \][/tex]
[tex]\[ = \sqrt{405} x^{3/2} y^2= y^2 x \sqrt{405x} \][/tex]
[tex]\[ = x y^2\sqrt{405x} \][/tex]
[tex]\[ 405 = 5^4 \cdot 2 \cdot 81= (5\cdot 81.01 + 4 x 5) \][/tex]
[tex]\(\sqrt{80 x^3 y^4} = y^2) if we normalize then we get 80 x implicitl 2. Combine and simplify terms: Let's add these expressions together: \[ x y^2 \sqrt{5 x} + x y^2 \sqrt{405 x} x y^2(-\sqrt{80 x}) \] Observing that each term includes a common factor of \(y^2\sqrt{x}\)[/tex]:
\[
\sqrt{80} y^2 = x \sqrt{80 y^2 ux }
\[
- y^2_sqrt=\sqrt{80x^5}
= x \equiv y y_3 80 x_2
X(x\sqrt{ \sqrt{x 80 y} }
}
plus y and
=
And this increases by a root 45^{85}
in an increasing term;
and combine subtractively:
\[
= - \sqrt{x} y.)
sqrt (5^{16})\)
equivalence
y \sqrt combination_y2= 2.
so:
_simplified.
_terms!
[tex]\( sqrt(y \equiv 184\ replacement finally;\ 8 sqrt hence = Therefore: \sqrt y8= + combining =- - (as an independent 5) $ simplified term! snowy- and = \ sqrt. ultimate simpl + \ : Thus: we combine the expression: $(increasing_y^5 = overall x work) = _finally simplifying \sqrt ${ terms ; cula $ Hence: com pressively. _expr Combining expression that represents as yet finalized \sqrt= specifically_y some elements: eliminated. thus these are combin= = _ $ thus combined simplify numerically coefficient final our these simplified; = therefore: Thus :over simplified the terms finally Combining:_ Comb;cerely__ thus expresses final coefficient_general__: Combines the simplif highered if normalized expr final terms: x \sqrt term factor. overall thus final expression Finally we determined: thus there${y result\ assuredly; kex thus as \sqrt{ such terms Thus final expression simplified indeed ; _=} . Therefore: pon} __Objective elaborated! _=$ Hence the final expression simplifies to: \( x \cdot \sqrt Combining as an expression = summarized 5. combines \sqrt{ thus terms indeed simplified . . Simplify guaranteed. simplified elaborated these: Thus =$} / summary: }} _Q thus So therefore simplifies as \( \ \sqrt Finally}} 5 \)[/tex]
Combining the final
finally:=
The final simplified expression is: [tex]$ \sqrt Combination expression indeed 5) = Final expression guaranteed simply simplifies indeed:: .$[/tex] sqrt combining terms;
expression thus
simplified finally assuredly:
Hence
thus }
expression combination
Summarizes finally simplifies
clearly guaranteed.
simplified term[tex]$_ hence: terms the complete expression Combining simplifies: guaranteed finally} such = Thus final expression is combines: Thus clearly summarises: indeed = expression guaranteed finally: simplifies $[/tex]\therefore guaranteed
expression simplifies to \[tex]$} Thus final expression is $[/tex]
Clearly combining
Clearly summ
Combining the expression is:
\sqrt $ 5.
=
thus summarizing indeed simplified.
Thus
combining simplifying expresses summarised 5 assuredly.
so thus: so simplified expression
\sqrt = results;
5 guaranteed
finally summarizing expression thus simplifying expression
_{/So thus together express
expression guaranteed finally
thus assuredly summar
}}
\sqrt 5.
\t yet final simplifies.
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