Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What is the vertical asymptote of the function [tex]\( f(x) = 3 \log (x+3) \)[/tex]?

The vertical asymptote of the function [tex]\( f(x) = 3 \log (x+3) \)[/tex] is [tex]\( x = \square \)[/tex].

Sagot :

To determine the vertical asymptote of the function [tex]\( f(x) = 3 \log (x + 3) \)[/tex], we need to consider where the argument of the logarithm is equal to zero since the logarithmic function becomes undefined at that point.

The argument of the logarithm in this function is [tex]\( x + 3 \)[/tex].

To find where this argument equals zero, we solve the equation:

[tex]\[ x + 3 = 0 \][/tex]

Subtract 3 from both sides:

[tex]\[ x = -3 \][/tex]

Therefore, the vertical asymptote of the function [tex]\( f(x) = 3 \log (x + 3) \)[/tex] is

[tex]\[ x = -3 \][/tex]

Thus, the correct answer is

[tex]\[ \boxed{-3} \][/tex]