Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine if the given table represents a function, we need to review the definition of a function. A function is a relationship between inputs and outputs where each input is associated with exactly one output.
Given the table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 2 & 1 \\ \hline 2 & 4 \\ \hline 3 & 4 \\ \hline 4 & 2 \\ \hline 5 & 5 \\ \hline \end{array} \][/tex]
Let's examine each pair of values:
1. For [tex]\( x = 2 \)[/tex], we have two corresponding [tex]\( y \)[/tex]-values: [tex]\( y = 1 \)[/tex] and [tex]\( y = 4 \)[/tex].
The key point to consider is that for [tex]\( x = 2 \)[/tex], there are two different [tex]\( y \)[/tex]-values (1 and 4). According to the definition of a function, each [tex]\( x \)[/tex]-value must correspond to exactly one [tex]\( y \)[/tex]-value. Since [tex]\( x = 2 \)[/tex] maps to two different [tex]\( y \)[/tex]-values, this violates the definition of a function.
As a result, the table does not represent a function.
Therefore, the correct answer is:
[tex]\[ \text{D. No, because one } x\text{-value corresponds to two different } y\text{-values.} \][/tex]
Given the table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 2 & 1 \\ \hline 2 & 4 \\ \hline 3 & 4 \\ \hline 4 & 2 \\ \hline 5 & 5 \\ \hline \end{array} \][/tex]
Let's examine each pair of values:
1. For [tex]\( x = 2 \)[/tex], we have two corresponding [tex]\( y \)[/tex]-values: [tex]\( y = 1 \)[/tex] and [tex]\( y = 4 \)[/tex].
The key point to consider is that for [tex]\( x = 2 \)[/tex], there are two different [tex]\( y \)[/tex]-values (1 and 4). According to the definition of a function, each [tex]\( x \)[/tex]-value must correspond to exactly one [tex]\( y \)[/tex]-value. Since [tex]\( x = 2 \)[/tex] maps to two different [tex]\( y \)[/tex]-values, this violates the definition of a function.
As a result, the table does not represent a function.
Therefore, the correct answer is:
[tex]\[ \text{D. No, because one } x\text{-value corresponds to two different } y\text{-values.} \][/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.