Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To determine if the given table represents a function, we need to review the definition of a function. A function is a relationship between inputs and outputs where each input is associated with exactly one output.
Given the table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 2 & 1 \\ \hline 2 & 4 \\ \hline 3 & 4 \\ \hline 4 & 2 \\ \hline 5 & 5 \\ \hline \end{array} \][/tex]
Let's examine each pair of values:
1. For [tex]\( x = 2 \)[/tex], we have two corresponding [tex]\( y \)[/tex]-values: [tex]\( y = 1 \)[/tex] and [tex]\( y = 4 \)[/tex].
The key point to consider is that for [tex]\( x = 2 \)[/tex], there are two different [tex]\( y \)[/tex]-values (1 and 4). According to the definition of a function, each [tex]\( x \)[/tex]-value must correspond to exactly one [tex]\( y \)[/tex]-value. Since [tex]\( x = 2 \)[/tex] maps to two different [tex]\( y \)[/tex]-values, this violates the definition of a function.
As a result, the table does not represent a function.
Therefore, the correct answer is:
[tex]\[ \text{D. No, because one } x\text{-value corresponds to two different } y\text{-values.} \][/tex]
Given the table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 2 & 1 \\ \hline 2 & 4 \\ \hline 3 & 4 \\ \hline 4 & 2 \\ \hline 5 & 5 \\ \hline \end{array} \][/tex]
Let's examine each pair of values:
1. For [tex]\( x = 2 \)[/tex], we have two corresponding [tex]\( y \)[/tex]-values: [tex]\( y = 1 \)[/tex] and [tex]\( y = 4 \)[/tex].
The key point to consider is that for [tex]\( x = 2 \)[/tex], there are two different [tex]\( y \)[/tex]-values (1 and 4). According to the definition of a function, each [tex]\( x \)[/tex]-value must correspond to exactly one [tex]\( y \)[/tex]-value. Since [tex]\( x = 2 \)[/tex] maps to two different [tex]\( y \)[/tex]-values, this violates the definition of a function.
As a result, the table does not represent a function.
Therefore, the correct answer is:
[tex]\[ \text{D. No, because one } x\text{-value corresponds to two different } y\text{-values.} \][/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.