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Sagot :
To find the value of [tex]\( t(6) \)[/tex] in the given piecewise function, we start by identifying which part of the function to use based on the value of [tex]\( x = 6 \)[/tex].
The function is defined as:
[tex]\[ y = \begin{cases} -3x + 19 & \text{if } x < 4 \\ \frac{x}{2} + 5 & \text{if } x \geq 4 \end{cases} \][/tex]
Since [tex]\( x = 6 \)[/tex] is greater than 4, we use the second part of the function:
[tex]\[ y = \frac{x}{2} + 5 \][/tex]
Now we substitute [tex]\( x = 6 \)[/tex] into this equation:
[tex]\[ y = \frac{6}{2} + 5 \][/tex]
First, we perform the division:
[tex]\[ \frac{6}{2} = 3 \][/tex]
Next, we add 5 to the result of the division:
[tex]\[ 3 + 5 = 8 \][/tex]
Therefore, the value of [tex]\( t(6) \)[/tex] is [tex]\( 8 \)[/tex].
So, [tex]\( t(6) = 8 \)[/tex].
The function is defined as:
[tex]\[ y = \begin{cases} -3x + 19 & \text{if } x < 4 \\ \frac{x}{2} + 5 & \text{if } x \geq 4 \end{cases} \][/tex]
Since [tex]\( x = 6 \)[/tex] is greater than 4, we use the second part of the function:
[tex]\[ y = \frac{x}{2} + 5 \][/tex]
Now we substitute [tex]\( x = 6 \)[/tex] into this equation:
[tex]\[ y = \frac{6}{2} + 5 \][/tex]
First, we perform the division:
[tex]\[ \frac{6}{2} = 3 \][/tex]
Next, we add 5 to the result of the division:
[tex]\[ 3 + 5 = 8 \][/tex]
Therefore, the value of [tex]\( t(6) \)[/tex] is [tex]\( 8 \)[/tex].
So, [tex]\( t(6) = 8 \)[/tex].
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