Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

The midpoint of [tex]\( \bar{E} \)[/tex] is point [tex]\( P \)[/tex] at [tex]\((-6,-2)\)[/tex]. If point [tex]\( E \)[/tex] is at [tex]\((2,-4)\)[/tex], what are the coordinates of point [tex]\( F \)[/tex]?

A. [tex]\((-14,0)\)[/tex]
B. [tex]\((-10,-8)\)[/tex]
C. [tex]\((-5,3)\)[/tex]


Sagot :

To solve for the coordinates of point [tex]\( F \)[/tex] given the midpoint [tex]\( P \)[/tex] of segment [tex]\( \bar{EF} \)[/tex] and the coordinates of point [tex]\( E \)[/tex], follow these steps:

1. Identify the given coordinates:
- Point [tex]\( P \)[/tex] is [tex]\((-6, -2)\)[/tex]
- Point [tex]\( E \)[/tex] is [tex]\((2, -4)\)[/tex]

2. Recall the midpoint formula:
[tex]\[ P = \left(\frac{x_E + x_F}{2}, \frac{y_E + y_F}{2}\right) \][/tex]
where [tex]\( (x_E, y_E) \)[/tex] are the coordinates of point [tex]\( E \)[/tex] and [tex]\( (x_F, y_F) \)[/tex] are the coordinates of point [tex]\( F \)[/tex].

3. Set up the equations for the midpoint coordinates:
- For the x-coordinate:
[tex]\[ -6 = \frac{2 + x_F}{2} \][/tex]
- For the y-coordinate:
[tex]\[ -2 = \frac{-4 + y_F}{2} \][/tex]

4. Solve for [tex]\( x_F \)[/tex] and [tex]\( y_F \)[/tex]:
- First, solve the x-coordinate equation:
[tex]\[ -6 = \frac{2 + x_F}{2} \][/tex]
Multiply both sides by 2 to eliminate the denominator:
[tex]\[ -12 = 2 + x_F \][/tex]
Subtract 2 from both sides:
[tex]\[ x_F = -14 \][/tex]

- Next, solve the y-coordinate equation:
[tex]\[ -2 = \frac{-4 + y_F}{2} \][/tex]
Multiply both sides by 2 to eliminate the denominator:
[tex]\[ -4 = -4 + y_F \][/tex]
Add 4 to both sides:
[tex]\[ y_F = 0 \][/tex]

5. Combine the results:
- The coordinates of point [tex]\( F \)[/tex] are [tex]\( (-14, 0) \)[/tex].

Thus, the coordinates of point [tex]\( F \)[/tex] are [tex]\( \boxed{(-14, 0)} \)[/tex].