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Christopher rents an apartment in a mixed-composition, suburban complex. The value of the belongings in the apartment is about [tex]$22,000. If Christopher wants to insure his belongings while renting, how much will he have to pay for insurance per year?

| Area | Brick | Steel | Mixed | Wood |
|--------|--------|--------|--------|-------|
| | Bldg | Cont | Bldg | Cont | Bldg | Cont | Bldg | Cont |
| City | 0.39 | 0.43 | 0.5 | 0.54 | 0.55 | 0.65 | 0.66 | 0.76 |
| Suburb | 0.45 | 0.52 | 0.56 | 0.63 | 0.72 | 0.74 | 0.83 | 0.85 |
| Rural | 0.6 | 0.69 | 0.71 | 0.8 | 0.89 | 0.91 | 1.00 | 1.02 |

A. $[/tex]107.50
B. [tex]$150.00
C. $[/tex]162.80
D. $178.65


Sagot :

To determine how much Christopher will have to pay for insurance per year for his belongings, we need to identify the relevant values from the table.

1. Identify the location and type of building: Based on the problem, Christopher rents an apartment in a suburban area, and the building composition is mixed.

2. Find the annual premium per [tex]$100 of coverage: From the row corresponding to the 'Suburb' line and under the 'Mixed' column for 'Contents,' we find the annual premium per $[/tex]100 of coverage is [tex]$0.74. 3. Calculate the total premium: - Value of belongings: $[/tex]22,000.

- Annual premium per [tex]$100: $[/tex]0.74.

To find the total annual premium, we multiply the value of the belongings by the annual premium per [tex]$100, as follows: \[ \text {Annual premium} = \left( \frac{\$[/tex] 22,000}{\[tex]$ 100} \right) \times 0.74 \] Simplifying inside the parentheses: \[ \frac{\$[/tex] 22,000}{\[tex]$ 100} = 220 \] Now multiply by the premium rate: \[ 220 \times 0.74 = 162.8 \] 4. Final answer: Christopher will have to pay $[/tex]\[tex]$ 162.80$[/tex] for insurance per year.

Thus, the correct answer is:

[tex]\[ \boxed{162.80} \][/tex]