Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine which of the given options represents the equation of the central street [tex]\(PQ\)[/tex], let's start by analyzing the equation of the lane passing through points [tex]\(A\)[/tex] and [tex]\(B\)[/tex]:
Given equation: [tex]\(-7x + 3y = -21.5\)[/tex]
To understand this equation better, let's find its slope. We can rearrange it into the slope-intercept form [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] represents the slope.
[tex]\[ -7x + 3y = -21.5 \][/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 3y = 7x - 21.5 \][/tex]
[tex]\[ y = \frac{7}{3}x - \frac{21.5}{3} \][/tex]
The slope [tex]\(m\)[/tex] of the line is [tex]\(\frac{7}{3}\)[/tex].
Now, we need to consider that the streets are either going to be parallel or perpendicular to this given lane.
1. If a line is parallel to the given lane, it will have the same slope [tex]\(\frac{7}{3}\)[/tex].
2. If a line is perpendicular to the given lane, its slope will be the negative reciprocal of [tex]\(\frac{7}{3}\)[/tex], which is [tex]\(-\frac{3}{7}\)[/tex].
Let's evaluate the slopes of the lines provided in the options:
### Option A: [tex]\(-3x + 4y = 3\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 4y = 3x + 3 \][/tex]
[tex]\[ y = \frac{3}{4}x + \frac{3}{4} \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(\frac{3}{4}\)[/tex], which is neither [tex]\(\frac{7}{3}\)[/tex] nor [tex]\(-\frac{3}{7}\)[/tex]. Therefore, this option is not correct.
### Option B: [tex]\(3x + 7y = 63\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 7y = -3x + 63 \][/tex]
[tex]\[ y = -\frac{3}{7}x + 9 \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(-\frac{3}{7}\)[/tex], which is the negative reciprocal of [tex]\(\frac{7}{3}\)[/tex]. This indicates that this line is perpendicular to the given lane. This option is correct.
### Option C: [tex]\(2x + y = 20\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ y = -2x + 20 \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(-2\)[/tex], which is neither [tex]\(\frac{7}{3}\)[/tex] nor [tex]\(-\frac{3}{7}\)[/tex]. Therefore, this option is not correct.
### Option D: [tex]\(7x + 3y = 70\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 3y = -7x + 70 \][/tex]
[tex]\[ y = -\frac{7}{3}x + \frac{70}{3} \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(-\frac{7}{3}\)[/tex], which is not relevant for our parallel or perpendicular condition. Therefore, this option is not correct.
Therefore, the correct equation for the central street [tex]\(PQ\)[/tex] is:
[tex]\[ \boxed{3x + 7y = 63} \][/tex]
Given equation: [tex]\(-7x + 3y = -21.5\)[/tex]
To understand this equation better, let's find its slope. We can rearrange it into the slope-intercept form [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] represents the slope.
[tex]\[ -7x + 3y = -21.5 \][/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 3y = 7x - 21.5 \][/tex]
[tex]\[ y = \frac{7}{3}x - \frac{21.5}{3} \][/tex]
The slope [tex]\(m\)[/tex] of the line is [tex]\(\frac{7}{3}\)[/tex].
Now, we need to consider that the streets are either going to be parallel or perpendicular to this given lane.
1. If a line is parallel to the given lane, it will have the same slope [tex]\(\frac{7}{3}\)[/tex].
2. If a line is perpendicular to the given lane, its slope will be the negative reciprocal of [tex]\(\frac{7}{3}\)[/tex], which is [tex]\(-\frac{3}{7}\)[/tex].
Let's evaluate the slopes of the lines provided in the options:
### Option A: [tex]\(-3x + 4y = 3\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 4y = 3x + 3 \][/tex]
[tex]\[ y = \frac{3}{4}x + \frac{3}{4} \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(\frac{3}{4}\)[/tex], which is neither [tex]\(\frac{7}{3}\)[/tex] nor [tex]\(-\frac{3}{7}\)[/tex]. Therefore, this option is not correct.
### Option B: [tex]\(3x + 7y = 63\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 7y = -3x + 63 \][/tex]
[tex]\[ y = -\frac{3}{7}x + 9 \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(-\frac{3}{7}\)[/tex], which is the negative reciprocal of [tex]\(\frac{7}{3}\)[/tex]. This indicates that this line is perpendicular to the given lane. This option is correct.
### Option C: [tex]\(2x + y = 20\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ y = -2x + 20 \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(-2\)[/tex], which is neither [tex]\(\frac{7}{3}\)[/tex] nor [tex]\(-\frac{3}{7}\)[/tex]. Therefore, this option is not correct.
### Option D: [tex]\(7x + 3y = 70\)[/tex]
- Isolate [tex]\(y\)[/tex]:
[tex]\[ 3y = -7x + 70 \][/tex]
[tex]\[ y = -\frac{7}{3}x + \frac{70}{3} \][/tex]
The slope [tex]\(m\)[/tex] of this line is [tex]\(-\frac{7}{3}\)[/tex], which is not relevant for our parallel or perpendicular condition. Therefore, this option is not correct.
Therefore, the correct equation for the central street [tex]\(PQ\)[/tex] is:
[tex]\[ \boxed{3x + 7y = 63} \][/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.