Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Let's factor the polynomial [tex]\(x^3 + x^2 + x + 1\)[/tex] by grouping. Here are the steps involved in the factorization process:
1. Group the terms in pairs:
[tex]\[ x^3 + x^2 + x + 1 = (x^3 + x^2) + (x + 1) \][/tex]
2. Factor out the common factors in each group:
[tex]\[ = x^2(x + 1) + 1(x + 1) \][/tex]
3. Notice that [tex]\(x + 1\)[/tex] is a common factor in both groups:
[tex]\[ = (x^2 + 1)(x + 1) \][/tex]
The polynomial [tex]\(x^3 + x^2 + x + 1\)[/tex] factors into [tex]\((x^2 + 1)(x + 1)\)[/tex].
Thus, the resulting expression is:
[tex]\[ \boxed{(x^2 + 1)(x + 1)} \][/tex]
So, from the given options, the correct answer is:
[tex]\[ \left(x^2+1\right)(x+1) \][/tex]
1. Group the terms in pairs:
[tex]\[ x^3 + x^2 + x + 1 = (x^3 + x^2) + (x + 1) \][/tex]
2. Factor out the common factors in each group:
[tex]\[ = x^2(x + 1) + 1(x + 1) \][/tex]
3. Notice that [tex]\(x + 1\)[/tex] is a common factor in both groups:
[tex]\[ = (x^2 + 1)(x + 1) \][/tex]
The polynomial [tex]\(x^3 + x^2 + x + 1\)[/tex] factors into [tex]\((x^2 + 1)(x + 1)\)[/tex].
Thus, the resulting expression is:
[tex]\[ \boxed{(x^2 + 1)(x + 1)} \][/tex]
So, from the given options, the correct answer is:
[tex]\[ \left(x^2+1\right)(x+1) \][/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.