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What is the y-intercept of this quadratic function?
[tex]\[ f(x) = -x^2 + 10x - 22 \][/tex]

The y-intercept of function [tex]\( f \)[/tex] is ( [tex]\(\square\)[/tex] , [tex]\(\square\)[/tex] ).

Sagot :

GinnyAnswer
To find the [tex]$y$[/tex]-intercept of the quadratic function [tex]\( f(x) = -x^2 + 10x - 22 \)[/tex], we need to evaluate the function at [tex]\( x = 0 \)[/tex].

Substitute [tex]\( x = 0 \)[/tex] into the function:
[tex]\[ f(0) = -(0)^2 + 10(0) - 22 \][/tex]
Simplifying this, we get:
[tex]\[ f(0) = -22 \][/tex]

Thus, the [tex]$y$[/tex]-intercept of the function [tex]\( f \)[/tex] is [tex]\( (0, -22) \)[/tex].

The [tex]$y$[/tex]-intercept of function [tex]$f$[/tex] is [tex]\( ( 0, -22 ) \)[/tex].
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