Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To solve the equation [tex]\(\sqrt{5y + 2} = \sqrt{3y + 14}\)[/tex], we will proceed step-by-step:
1. Square Both Sides:
To eliminate the square roots, square both sides of the equation. This gives us:
[tex]\[ (\sqrt{5y + 2})^2 = (\sqrt{3y + 14})^2 \][/tex]
Simplifying both sides, we get:
[tex]\[ 5y + 2 = 3y + 14 \][/tex]
2. Isolate the Variable [tex]\(y\)[/tex]:
To isolate [tex]\(y\)[/tex], we need to move the terms involving [tex]\(y\)[/tex] to one side and constants to the other. First, subtract [tex]\(3y\)[/tex] from both sides:
[tex]\[ 5y + 2 - 3y = 3y + 14 - 3y \][/tex]
Simplifying this, we get:
[tex]\[ 2y + 2 = 14 \][/tex]
3. Solve for [tex]\(y\)[/tex]:
Next, subtract 2 from both sides to isolate the term with [tex]\(y\)[/tex]:
[tex]\[ 2y + 2 - 2 = 14 - 2 \][/tex]
This simplifies to:
[tex]\[ 2y = 12 \][/tex]
Finally, divide both sides by 2 to solve for [tex]\(y\)[/tex]:
[tex]\[ y = \frac{12}{2} \][/tex]
[tex]\[ y = 6 \][/tex]
4. Verify the Solution:
To ensure that our solution is correct, substitute [tex]\(y = 6\)[/tex] back into the original equation:
[tex]\[ \sqrt{5(6) + 2} = \sqrt{3(6) + 14} \][/tex]
Simplifying inside the square roots:
[tex]\[ \sqrt{30 + 2} = \sqrt{18 + 14} \][/tex]
[tex]\[ \sqrt{32} = \sqrt{32} \][/tex]
Both sides are equal, confirming our solution.
Therefore, the solution to the equation [tex]\(\sqrt{5y + 2} = \sqrt{3y + 14}\)[/tex] is:
[tex]\[ y = 6 \][/tex]
1. Square Both Sides:
To eliminate the square roots, square both sides of the equation. This gives us:
[tex]\[ (\sqrt{5y + 2})^2 = (\sqrt{3y + 14})^2 \][/tex]
Simplifying both sides, we get:
[tex]\[ 5y + 2 = 3y + 14 \][/tex]
2. Isolate the Variable [tex]\(y\)[/tex]:
To isolate [tex]\(y\)[/tex], we need to move the terms involving [tex]\(y\)[/tex] to one side and constants to the other. First, subtract [tex]\(3y\)[/tex] from both sides:
[tex]\[ 5y + 2 - 3y = 3y + 14 - 3y \][/tex]
Simplifying this, we get:
[tex]\[ 2y + 2 = 14 \][/tex]
3. Solve for [tex]\(y\)[/tex]:
Next, subtract 2 from both sides to isolate the term with [tex]\(y\)[/tex]:
[tex]\[ 2y + 2 - 2 = 14 - 2 \][/tex]
This simplifies to:
[tex]\[ 2y = 12 \][/tex]
Finally, divide both sides by 2 to solve for [tex]\(y\)[/tex]:
[tex]\[ y = \frac{12}{2} \][/tex]
[tex]\[ y = 6 \][/tex]
4. Verify the Solution:
To ensure that our solution is correct, substitute [tex]\(y = 6\)[/tex] back into the original equation:
[tex]\[ \sqrt{5(6) + 2} = \sqrt{3(6) + 14} \][/tex]
Simplifying inside the square roots:
[tex]\[ \sqrt{30 + 2} = \sqrt{18 + 14} \][/tex]
[tex]\[ \sqrt{32} = \sqrt{32} \][/tex]
Both sides are equal, confirming our solution.
Therefore, the solution to the equation [tex]\(\sqrt{5y + 2} = \sqrt{3y + 14}\)[/tex] is:
[tex]\[ y = 6 \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.