Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
To determine the correct equation for a circle with radius [tex]\( r \)[/tex] and center at [tex]\( (h, k) \)[/tex], we need to recall the general form of the equation for a circle.
The standard equation of a circle with center [tex]\((h, k)\)[/tex] and radius [tex]\( r \)[/tex] is given by:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Let's analyze each of the provided options to find the one that matches this standard form.
A. [tex]\((x - k)^2 + (y - h)^2 = r^2\)[/tex]
This equation incorrectly switches the variables [tex]\( h \)[/tex] and [tex]\( k \)[/tex] as coordinates in the equation. The correct form doesn't swap these variables; it should have the form [tex]\((x - h)\)[/tex] and [tex]\((y - k)\)[/tex].
B. [tex]\(h^2 + k^2 = r^2\)[/tex]
This equation does not represent a circle’s equation in Cartesian coordinates. It looks like a Pythagorean theorem but does not fit the standard form of a circle.
C. [tex]\((x + h)^2 + (y + k)^2 = r^2\)[/tex]
This option incorrectly includes addition instead of subtraction. The standard form includes the subtraction of the center coordinates from the x and y coordinates, respectively.
D. [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex]
This matches the standard form exactly, with the correct subtraction of [tex]\( h \)[/tex] from [tex]\( x \)[/tex] and [tex]\( k \)[/tex] from [tex]\( y \)[/tex].
Thus, the correct equation for a circle with radius [tex]\( r \)[/tex] and center at [tex]\( (h, k) \)[/tex] is:
[tex]\[ \boxed{(x - h)^2 + (y - k)^2 = r^2} \][/tex]
So, the correct answer is option D.
The standard equation of a circle with center [tex]\((h, k)\)[/tex] and radius [tex]\( r \)[/tex] is given by:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Let's analyze each of the provided options to find the one that matches this standard form.
A. [tex]\((x - k)^2 + (y - h)^2 = r^2\)[/tex]
This equation incorrectly switches the variables [tex]\( h \)[/tex] and [tex]\( k \)[/tex] as coordinates in the equation. The correct form doesn't swap these variables; it should have the form [tex]\((x - h)\)[/tex] and [tex]\((y - k)\)[/tex].
B. [tex]\(h^2 + k^2 = r^2\)[/tex]
This equation does not represent a circle’s equation in Cartesian coordinates. It looks like a Pythagorean theorem but does not fit the standard form of a circle.
C. [tex]\((x + h)^2 + (y + k)^2 = r^2\)[/tex]
This option incorrectly includes addition instead of subtraction. The standard form includes the subtraction of the center coordinates from the x and y coordinates, respectively.
D. [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex]
This matches the standard form exactly, with the correct subtraction of [tex]\( h \)[/tex] from [tex]\( x \)[/tex] and [tex]\( k \)[/tex] from [tex]\( y \)[/tex].
Thus, the correct equation for a circle with radius [tex]\( r \)[/tex] and center at [tex]\( (h, k) \)[/tex] is:
[tex]\[ \boxed{(x - h)^2 + (y - k)^2 = r^2} \][/tex]
So, the correct answer is option D.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.