Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To determine the correct equation for a circle with radius [tex]\( r \)[/tex] and center at [tex]\( (h, k) \)[/tex], we need to recall the general form of the equation for a circle.
The standard equation of a circle with center [tex]\((h, k)\)[/tex] and radius [tex]\( r \)[/tex] is given by:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Let's analyze each of the provided options to find the one that matches this standard form.
A. [tex]\((x - k)^2 + (y - h)^2 = r^2\)[/tex]
This equation incorrectly switches the variables [tex]\( h \)[/tex] and [tex]\( k \)[/tex] as coordinates in the equation. The correct form doesn't swap these variables; it should have the form [tex]\((x - h)\)[/tex] and [tex]\((y - k)\)[/tex].
B. [tex]\(h^2 + k^2 = r^2\)[/tex]
This equation does not represent a circle’s equation in Cartesian coordinates. It looks like a Pythagorean theorem but does not fit the standard form of a circle.
C. [tex]\((x + h)^2 + (y + k)^2 = r^2\)[/tex]
This option incorrectly includes addition instead of subtraction. The standard form includes the subtraction of the center coordinates from the x and y coordinates, respectively.
D. [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex]
This matches the standard form exactly, with the correct subtraction of [tex]\( h \)[/tex] from [tex]\( x \)[/tex] and [tex]\( k \)[/tex] from [tex]\( y \)[/tex].
Thus, the correct equation for a circle with radius [tex]\( r \)[/tex] and center at [tex]\( (h, k) \)[/tex] is:
[tex]\[ \boxed{(x - h)^2 + (y - k)^2 = r^2} \][/tex]
So, the correct answer is option D.
The standard equation of a circle with center [tex]\((h, k)\)[/tex] and radius [tex]\( r \)[/tex] is given by:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Let's analyze each of the provided options to find the one that matches this standard form.
A. [tex]\((x - k)^2 + (y - h)^2 = r^2\)[/tex]
This equation incorrectly switches the variables [tex]\( h \)[/tex] and [tex]\( k \)[/tex] as coordinates in the equation. The correct form doesn't swap these variables; it should have the form [tex]\((x - h)\)[/tex] and [tex]\((y - k)\)[/tex].
B. [tex]\(h^2 + k^2 = r^2\)[/tex]
This equation does not represent a circle’s equation in Cartesian coordinates. It looks like a Pythagorean theorem but does not fit the standard form of a circle.
C. [tex]\((x + h)^2 + (y + k)^2 = r^2\)[/tex]
This option incorrectly includes addition instead of subtraction. The standard form includes the subtraction of the center coordinates from the x and y coordinates, respectively.
D. [tex]\((x - h)^2 + (y - k)^2 = r^2\)[/tex]
This matches the standard form exactly, with the correct subtraction of [tex]\( h \)[/tex] from [tex]\( x \)[/tex] and [tex]\( k \)[/tex] from [tex]\( y \)[/tex].
Thus, the correct equation for a circle with radius [tex]\( r \)[/tex] and center at [tex]\( (h, k) \)[/tex] is:
[tex]\[ \boxed{(x - h)^2 + (y - k)^2 = r^2} \][/tex]
So, the correct answer is option D.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.