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What is the equation of the circle with center [tex]\((-3.2, -2.1)\)[/tex] and radius 4.3?

A. [tex]\((x + 3.2)^2 + (y - 2.1)^2 = 4.3^2\)[/tex]
B. [tex]\((x - 2.1)^2 - (y + 3.2)^2 = (4.3)^2\)[/tex]
C. [tex]\((x + 3.2)^2 + (y + 2.1)^2 = (4.3)^2\)[/tex]
D. [tex]\((x + 2.1)^2 + (y - 3.2)^2 = 4.3^2\)[/tex]


Sagot :

To find the equation of the circle given the center [tex]\((-3.2, -2.1)\)[/tex] and the radius 4.3, we use the standard form of the equation of a circle:

[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]

where [tex]\((h, k)\)[/tex] is the center of the circle and [tex]\(r\)[/tex] is the radius.

Given:
- The center [tex]\((h, k) = (-3.2, -2.1)\)[/tex]
- The radius [tex]\(r = 4.3\)[/tex]

We substitute these values into the standard form:

1. [tex]\(h = -3.2\)[/tex] and [tex]\(k = -2.1\)[/tex]
2. [tex]\(r = 4.3\)[/tex]

Thus, the equation becomes:

[tex]\[ (x - (-3.2))^2 + (y - (-2.1))^2 = (4.3)^2 \][/tex]

This simplifies to:

[tex]\[ (x + 3.2)^2 + (y + 2.1)^2 = 4.3^2 \][/tex]

Now, we match this equation to the given choices:

A. [tex]\((x+3.2)^2+(y-2.1)^2=4.3^2\)[/tex]

B. [tex]\((x-2.1)^2-(y+3.2)^2=(4.3)^2\)[/tex]

C. [tex]\((x+3.2)^2+(y+2.1)^2=(4.3)^2\)[/tex]

D. [tex]\((x+2.1)^2+(y-3.2)^2=4.3^2\)[/tex]

The correct equation that matches ours is:

C. [tex]\((x+3.2)^2+(y+2.1)^2=(4.3)^2\)[/tex]

Therefore, the correct choice is:

[tex]\[ \boxed{3} \][/tex]