Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine the spectator ions in the reaction [tex]\( Mg (s) + Zn^{2+} + 2NO_3^{-} \rightarrow Mg^{2+} + 2NO_3^{-} + Zn (s) \)[/tex], we need to identify the ions that remain unchanged and do not participate in the chemical change. Let's break down the process step-by-step:
1. Identify the Reactants and Products:
- Reactants: [tex]\( Mg (s) \)[/tex], [tex]\( Zn^{2+} \)[/tex], [tex]\( 2NO_3^{-} \)[/tex]
- Products: [tex]\( Mg^{2+} \)[/tex], [tex]\( 2NO_3^{-} \)[/tex], [tex]\( Zn (s) \)[/tex]
2. Determine Changes in Oxidation State:
- [tex]\( Mg (s) \)[/tex] changes to [tex]\( Mg^{2+} \)[/tex] (Magnesium solid to magnesium ion)
- [tex]\( Zn^{2+} \)[/tex] changes to [tex]\( Zn (s) \)[/tex] (Zinc ion to zinc solid)
- [tex]\( NO_3^{-} \)[/tex] stays [tex]\( NO_3^{-} \)[/tex] (Nitrate ion remains unchanged)
3. Identify Spectator Ions:
- Spectator ions are those ions that appear the same on both reactant and product sides of the equation and do not undergo any change in oxidation state.
- In this reaction, [tex]\( NO_3^{-} \)[/tex] appears unchanged as [tex]\( 2NO_3^{-} \)[/tex] on both sides of the equation.
Therefore, the spectator ions in this reaction are [tex]\( NO_3^{-} \)[/tex].
Based on the options:
A. [tex]\( Zn^{2+} \)[/tex] and [tex]\( Mg^{2+} \)[/tex]: Incorrect, these change during the reaction.
B. [tex]\( Mg (s) \)[/tex] and [tex]\( Zn (s) \)[/tex]: Incorrect, these are not ions and they also change state.
C. [tex]\( NO_3^{-}; Zn^{2+}\)[/tex], and [tex]\( Mg^{2+} \)[/tex]: Incorrect, only [tex]\( NO_3^{-} \)[/tex] is unchanged.
D. [tex]\( NO_3^{-} \)[/tex]: Correct, nitrate ions remain unchanged in the reaction.
Thus, the correct answer is D. [tex]\( NO_3^{-} \)[/tex].
1. Identify the Reactants and Products:
- Reactants: [tex]\( Mg (s) \)[/tex], [tex]\( Zn^{2+} \)[/tex], [tex]\( 2NO_3^{-} \)[/tex]
- Products: [tex]\( Mg^{2+} \)[/tex], [tex]\( 2NO_3^{-} \)[/tex], [tex]\( Zn (s) \)[/tex]
2. Determine Changes in Oxidation State:
- [tex]\( Mg (s) \)[/tex] changes to [tex]\( Mg^{2+} \)[/tex] (Magnesium solid to magnesium ion)
- [tex]\( Zn^{2+} \)[/tex] changes to [tex]\( Zn (s) \)[/tex] (Zinc ion to zinc solid)
- [tex]\( NO_3^{-} \)[/tex] stays [tex]\( NO_3^{-} \)[/tex] (Nitrate ion remains unchanged)
3. Identify Spectator Ions:
- Spectator ions are those ions that appear the same on both reactant and product sides of the equation and do not undergo any change in oxidation state.
- In this reaction, [tex]\( NO_3^{-} \)[/tex] appears unchanged as [tex]\( 2NO_3^{-} \)[/tex] on both sides of the equation.
Therefore, the spectator ions in this reaction are [tex]\( NO_3^{-} \)[/tex].
Based on the options:
A. [tex]\( Zn^{2+} \)[/tex] and [tex]\( Mg^{2+} \)[/tex]: Incorrect, these change during the reaction.
B. [tex]\( Mg (s) \)[/tex] and [tex]\( Zn (s) \)[/tex]: Incorrect, these are not ions and they also change state.
C. [tex]\( NO_3^{-}; Zn^{2+}\)[/tex], and [tex]\( Mg^{2+} \)[/tex]: Incorrect, only [tex]\( NO_3^{-} \)[/tex] is unchanged.
D. [tex]\( NO_3^{-} \)[/tex]: Correct, nitrate ions remain unchanged in the reaction.
Thus, the correct answer is D. [tex]\( NO_3^{-} \)[/tex].
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.