Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To simplify the given expression [tex]\(\frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}}\)[/tex], we will break it down step by step.
1. Simplify the Cube Roots Separately:
First, let's simplify the numerators and denominators inside the cube roots.
The numerator is [tex]\(\sqrt[3]{32 x^3 y^6}\)[/tex]:
[tex]\[ \sqrt[3]{32 x^3 y^6} = 32^{1/3} \cdot (x^3)^{1/3} \cdot (y^6)^{1/3} \][/tex]
Simplifying each term individually:
[tex]\[ 32^{1/3} = 2^{5/3} = 2 \cdot 2^{2/3} \][/tex]
[tex]\[ (x^3)^{1/3} = x \][/tex]
[tex]\[ (y^6)^{1/3} = y^2 \][/tex]
So,
[tex]\[ \sqrt[3]{32 x^3 y^6} = 2 \cdot x \cdot y^2 \cdot 2^{2/3} = 2 \cdot 2^{2/3} \cdot x \cdot y^2 \][/tex]
Next, let's simplify the denominator [tex]\(\sqrt[3]{2 x^9 y^2}\)[/tex]:
[tex]\[ \sqrt[3]{2 x^9 y^2} = (2)^{1/3} \cdot (x^9)^{1/3} \cdot (y^2)^{1/3} \][/tex]
Simplifying each term individually:
[tex]\[ 2^{1/3} \][/tex]
[tex]\[ (x^9)^{1/3} = x^3 \][/tex]
[tex]\[ (y^2)^{1/3} = y^{2/3} \][/tex]
So,
[tex]\[ \sqrt[3]{2 x^9 y^2} = 2^{1/3} \cdot x^3 \cdot y^{2/3} \][/tex]
2. Combine the Simplified Forms:
Now we put the simplified numerator and denominator together:
[tex]\[ \frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}} = \frac{2 \cdot 2^{2/3} \cdot x \cdot y^2}{2^{1/3} \cdot x^3 \cdot y^{2/3}} \][/tex]
3. Simplify the Fraction:
We can simplify this by canceling like terms and combining the powers of 2:
[tex]\[ \frac{2 \cdot 2^{2/3}}{2^{1/3}} = 2^{1 + 2/3 - 1/3} = 2^{4/3} \][/tex]
For the [tex]\(x\)[/tex] terms:
[tex]\[ \frac{x}{x^3} = x^{1-3} = x^{-2} \][/tex]
For the [tex]\(y\)[/tex] terms:
[tex]\[ \frac{y^2}{y^{2/3}} = y^{2 - 2/3} = y^{4/3} \][/tex]
Thus, the simplified form is:
[tex]\[ 2^{4/3} \cdot x^{-2} \cdot y^{4/3} \][/tex]
But [tex]\(2^{4/3} = (2^{1/3})^4\)[/tex], simplifying it separately:
[tex]\[ (2^{1/3})^4 = 2^{4/3} \][/tex]
Hence, the expression becomes:
[tex]\[ \frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}} = 2^{4/3} \cdot x^{-2} \cdot y^{4/3} \][/tex]
Therefore, the equivalent simplified form of [tex]\(\frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}}\)[/tex] is:
[tex]\[ 2^{4/3} \cdot \frac{y^{4/3}}{x^2} \][/tex]
1. Simplify the Cube Roots Separately:
First, let's simplify the numerators and denominators inside the cube roots.
The numerator is [tex]\(\sqrt[3]{32 x^3 y^6}\)[/tex]:
[tex]\[ \sqrt[3]{32 x^3 y^6} = 32^{1/3} \cdot (x^3)^{1/3} \cdot (y^6)^{1/3} \][/tex]
Simplifying each term individually:
[tex]\[ 32^{1/3} = 2^{5/3} = 2 \cdot 2^{2/3} \][/tex]
[tex]\[ (x^3)^{1/3} = x \][/tex]
[tex]\[ (y^6)^{1/3} = y^2 \][/tex]
So,
[tex]\[ \sqrt[3]{32 x^3 y^6} = 2 \cdot x \cdot y^2 \cdot 2^{2/3} = 2 \cdot 2^{2/3} \cdot x \cdot y^2 \][/tex]
Next, let's simplify the denominator [tex]\(\sqrt[3]{2 x^9 y^2}\)[/tex]:
[tex]\[ \sqrt[3]{2 x^9 y^2} = (2)^{1/3} \cdot (x^9)^{1/3} \cdot (y^2)^{1/3} \][/tex]
Simplifying each term individually:
[tex]\[ 2^{1/3} \][/tex]
[tex]\[ (x^9)^{1/3} = x^3 \][/tex]
[tex]\[ (y^2)^{1/3} = y^{2/3} \][/tex]
So,
[tex]\[ \sqrt[3]{2 x^9 y^2} = 2^{1/3} \cdot x^3 \cdot y^{2/3} \][/tex]
2. Combine the Simplified Forms:
Now we put the simplified numerator and denominator together:
[tex]\[ \frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}} = \frac{2 \cdot 2^{2/3} \cdot x \cdot y^2}{2^{1/3} \cdot x^3 \cdot y^{2/3}} \][/tex]
3. Simplify the Fraction:
We can simplify this by canceling like terms and combining the powers of 2:
[tex]\[ \frac{2 \cdot 2^{2/3}}{2^{1/3}} = 2^{1 + 2/3 - 1/3} = 2^{4/3} \][/tex]
For the [tex]\(x\)[/tex] terms:
[tex]\[ \frac{x}{x^3} = x^{1-3} = x^{-2} \][/tex]
For the [tex]\(y\)[/tex] terms:
[tex]\[ \frac{y^2}{y^{2/3}} = y^{2 - 2/3} = y^{4/3} \][/tex]
Thus, the simplified form is:
[tex]\[ 2^{4/3} \cdot x^{-2} \cdot y^{4/3} \][/tex]
But [tex]\(2^{4/3} = (2^{1/3})^4\)[/tex], simplifying it separately:
[tex]\[ (2^{1/3})^4 = 2^{4/3} \][/tex]
Hence, the expression becomes:
[tex]\[ \frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}} = 2^{4/3} \cdot x^{-2} \cdot y^{4/3} \][/tex]
Therefore, the equivalent simplified form of [tex]\(\frac{\sqrt[3]{32 x^3 y^6}}{\sqrt[3]{2 x^9 y^2}}\)[/tex] is:
[tex]\[ 2^{4/3} \cdot \frac{y^{4/3}}{x^2} \][/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.