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Roy and Elisa are buying tickets for the annual school concert. Roy buys 6 adult tickets and 2 child tickets for a total of [tex]$66. Elisa buys 5 adult tickets and 4 child tickets for a total of $[/tex]62.

Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be used.

Determine the system of equations that can be used to find the cost of one adult ticket, [tex]\(a\)[/tex], and the cost of one child ticket, [tex]\(c\)[/tex].

Numbers to use:
4, 6, 5, 66, 128, 8, 62, 2

Equations:
Roy: [tex]\( \_a + \_c = 66 \)[/tex]
Elisa: [tex]\( \_a + \_c = 62 \)[/tex]

Sagot :

GinnyAnswer
To determine the system of equations based on the given information:

### Roy's Purchase:
Roy buys 6 adult tickets and 2 child tickets for a total of [tex]$66. Thus, the equation can be written as: \[ 6a + 2c = 66 \] ### Elisa's Purchase: Elisa buys 5 adult tickets and 4 child tickets for a total of $[/tex]62.

Thus, the equation can be written as:
[tex]\[ 5a + 4c = 62 \][/tex]

### Dragging the Numbers to the Correct Locations:

- For Roy: [tex]\(6a + 2c = 66\)[/tex]
- 6 (for [tex]\(6a\)[/tex])
- 2 (for [tex]\(2c\)[/tex])
- 66 (for the total cost)

- For Elisa: [tex]\(5a + 4c = 62\)[/tex]
- 5 (for [tex]\(5a\)[/tex])
- 4 (for [tex]\(4c\)[/tex])
- 62 (for the total cost)

### Final Equations:
- Roy: [tex]\( 6a + 2c = 66 \)[/tex]
- Elisa: [tex]\( 5a + 4c = 62 \)[/tex]

This completes the system of equations you can use to find the cost of one adult ticket ([tex]\(a\)[/tex]) and one child ticket ([tex]\(c\)[/tex]).
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