Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To find the zeros of the polynomial function [tex]\( f(x) = x^3 + 4x^2 - 9x - 36 \)[/tex], we need to determine the values of [tex]\( x \)[/tex] for which [tex]\( f(x) = 0 \)[/tex]. Here is the step-by-step process to solve for the zeros:
1. Define the Polynomial Equation:
[tex]\[ f(x) = x^3 + 4x^2 - 9x - 36 \][/tex]
2. Set the Polynomial Equal to Zero:
[tex]\[ x^3 + 4x^2 - 9x - 36 = 0 \][/tex]
3. Find the Zeros:
Solving this cubic equation exactly can sometimes be challenging and often requires various algebraic techniques such as factoring, graphing, or numerical methods. However, in this particular instance, the solutions for the equation are:
[tex]\[ x = -4, \quad x = -3, \quad x = 3 \][/tex]
4. Verify the Solutions:
Let's verify these by substituting them back into the original polynomial equation to check if they yield zero.
- For [tex]\( x = -4 \)[/tex]:
[tex]\[ (-4)^3 + 4(-4)^2 - 9(-4) - 36 = -64 + 64 + 36 - 36 = 0 \][/tex]
- For [tex]\( x = -3 \)[/tex]:
[tex]\[ (-3)^3 + 4(-3)^2 - 9(-3) - 36 = -27 + 36 + 27 - 36 = 0 \][/tex]
- For [tex]\( x = 3 \)[/tex]:
[tex]\[ 3^3 + 4(3)^2 - 9(3) - 36 = 27 + 36 - 27 - 36 = 0 \][/tex]
Each substitution yields zero, confirming that [tex]\( x = -4 \)[/tex], [tex]\( x = -3 \)[/tex], and [tex]\( x = 3 \)[/tex] are indeed the zeros of the polynomial function.
Therefore, the zeros of the polynomial function [tex]\( f(x) = x^3 + 4x^2 - 9x - 36 \)[/tex] are:
[tex]\[ \boxed{-4, -3, 3} \][/tex]
1. Define the Polynomial Equation:
[tex]\[ f(x) = x^3 + 4x^2 - 9x - 36 \][/tex]
2. Set the Polynomial Equal to Zero:
[tex]\[ x^3 + 4x^2 - 9x - 36 = 0 \][/tex]
3. Find the Zeros:
Solving this cubic equation exactly can sometimes be challenging and often requires various algebraic techniques such as factoring, graphing, or numerical methods. However, in this particular instance, the solutions for the equation are:
[tex]\[ x = -4, \quad x = -3, \quad x = 3 \][/tex]
4. Verify the Solutions:
Let's verify these by substituting them back into the original polynomial equation to check if they yield zero.
- For [tex]\( x = -4 \)[/tex]:
[tex]\[ (-4)^3 + 4(-4)^2 - 9(-4) - 36 = -64 + 64 + 36 - 36 = 0 \][/tex]
- For [tex]\( x = -3 \)[/tex]:
[tex]\[ (-3)^3 + 4(-3)^2 - 9(-3) - 36 = -27 + 36 + 27 - 36 = 0 \][/tex]
- For [tex]\( x = 3 \)[/tex]:
[tex]\[ 3^3 + 4(3)^2 - 9(3) - 36 = 27 + 36 - 27 - 36 = 0 \][/tex]
Each substitution yields zero, confirming that [tex]\( x = -4 \)[/tex], [tex]\( x = -3 \)[/tex], and [tex]\( x = 3 \)[/tex] are indeed the zeros of the polynomial function.
Therefore, the zeros of the polynomial function [tex]\( f(x) = x^3 + 4x^2 - 9x - 36 \)[/tex] are:
[tex]\[ \boxed{-4, -3, 3} \][/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.