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For the line segment with endpoints [tex]\( L(0,1) \)[/tex] and [tex]\( M(2,8) \)[/tex], find the [tex]\( y \)[/tex] value for the point located [tex]\(\frac{3}{5}\)[/tex] the distance from [tex]\( L \)[/tex] to [tex]\( M \)[/tex].

A. 5.2
B. 3.5
C. 4.8
D. 1.6


Sagot :

To find the [tex]\(y\)[/tex] value for the point located [tex]\(\frac{3}{5}\)[/tex] the distance from [tex]\(L(0, 1)\)[/tex] to [tex]\(M(2, 8)\)[/tex], we need to understand the concept of a point partitioning a line segment in a given ratio.

Here are the steps:

1. Identify coordinates of points L and M:
- Point [tex]\(L\)[/tex] has coordinates [tex]\((0, 1)\)[/tex].
- Point [tex]\(M\)[/tex] has coordinates [tex]\((2, 8)\)[/tex].

2. Determine the fraction of the distance:
- The point is [tex]\(\frac{3}{5}\)[/tex] of the way from [tex]\(L\)[/tex] to [tex]\(M\)[/tex].

3. Calculate the change in [tex]\(x\)[/tex] and [tex]\(y\)[/tex] from [tex]\(L\)[/tex] to [tex]\(M\)[/tex]:
- For [tex]\(L\)[/tex] to [tex]\(M\)[/tex], the change in [tex]\(x\)[/tex] is [tex]\( x_M - x_L = 2 - 0 = 2 \)[/tex].
- For [tex]\(L\)[/tex] to [tex]\(M\)[/tex], the change in [tex]\(y\)[/tex] is [tex]\( y_M - y_L = 8 - 1 = 7 \)[/tex].

4. Determine the coordinates of the point that is [tex]\(\frac{3}{5}\)[/tex] the distance from [tex]\(L\)[/tex] to [tex]\(M\)[/tex]:
- The [tex]\(x\)[/tex]-coordinate of the new point is [tex]\( x_L + \frac{3}{5} \times (x_M - x_L) \)[/tex]:
[tex]\[ x_{\text{new}} = 0 + \frac{3}{5} \times 2 = \frac{6}{5} = 1.2 \][/tex]
- The [tex]\(y\)[/tex]-coordinate of the new point is [tex]\( y_L + \frac{3}{5} \times (y_M - y_L) \)[/tex]:
[tex]\[ y_{\text{new}} = 1 + \frac{3}{5} \times 7 = 1 + \frac{21}{5} = 1 + 4.2 = 5.2 \][/tex]

Thus, the [tex]\(y\)[/tex] value for the point located [tex]\(\frac{3}{5}\)[/tex] the distance from [tex]\(L\)[/tex] to [tex]\(M\)[/tex] is [tex]\(5.2\)[/tex].

Given the choices:
- [tex]\(6\)[/tex]
- [tex]\(5.2\)[/tex]
- [tex]\(3.5\)[/tex]
- [tex]\(4.8\)[/tex]
- [tex]\(1.6\)[/tex]

The correct answer is [tex]\(\boxed{5.2}\)[/tex].