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Solve the equation:

(x - 3)(x + 2) = 0

Enter the solution with the lowest value.

Sagot :

To solve the quadratic equation [tex]\((x-3)(x+2) = 0\)[/tex], we can use the Zero Product Property, which states that if the product of two factors is zero, then at least one of the factors must be zero.

Given the equation:
[tex]\[ (x - 3)(x + 2) = 0 \][/tex]

We can set each factor equal to zero and solve for [tex]\(x\)[/tex]:

1. For the first factor:
[tex]\[ x - 3 = 0 \][/tex]

Add 3 to both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ x = 3 \][/tex]

2. For the second factor:
[tex]\[ x + 2 = 0 \][/tex]

Subtract 2 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ x = -2 \][/tex]

So, the solutions to the equation [tex]\((x-3)(x+2) = 0\)[/tex] are [tex]\(x = 3\)[/tex] and [tex]\(x = -2\)[/tex].

The solution with the lowest value is:
[tex]\[ x = -2 \][/tex]