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To calculate the hourly revenue from the buffet after [tex]$x$[/tex] $1 increases, multiply the price paid by each customer and the average number of customers per hour. Create an inequality in standard form that represents the restaurant owner's desired revenue.

Type the correct answer in each box. Use numerals instead of words.

[tex]\[\square x^2 + \square x + \square \geq \square\][/tex]

Sagot :

To determine the coefficients of the inequality that represents the restaurant owner's desired revenue, let's go through the steps in detail.

1. We need to form a quadratic inequality that models the revenue of the buffet after [tex]$x$[/tex] \[tex]$1 increases in the price. 2. Let's establish our variables: - Customers per hour: 25 (average number of customers per hour) - Base price per customer: $[/tex]10 (initial price before any increases)
- Desired revenue: [tex]$500 (target revenue the restaurant owner wants to achieve) 3. With each $[/tex]1 increase in price, the total price per customer becomes [tex]$(10 + x)$[/tex].

4. The revenue function [tex]\( R \)[/tex] described by the price increase and the number of customers can be modeled as:
[tex]\[ R(x) = (10 + x) \times (25 - x) \][/tex]

Here, as the price increases, the number of customers decreases at an assumed rate of 1 customer lost per \[tex]$1 increase in price. 5. To find the inequality standard form \( a \cdot x^2 + b \cdot x + c \leq 0 \), we first expand the revenue function: \[ R(x) = (10 + x)(25 - x) \] 6. Expanding this: \[ R(x) = 10 \cdot 25 + 10 \cdot (-x) + x \cdot 25 + x \cdot (-x) \] \[ R(x) = 250 - 10x + 25x - x^2 \] \[ R(x) = 250 + 15x - x^2 \] \[ R(x) = -x^2 + 15x + 250 \] 7. The revenue must be at least \( \$[/tex]500 \):
[tex]\[ R(x) \geq 500 \][/tex]
Converting this to standard form:
[tex]\[ -x^2 + 15x + 250 \geq 500 \][/tex]
[tex]\[ -x^2 + 15x + 250 - 500 \geq 0 \][/tex]
[tex]\[ -x^2 + 15x - 250 \geq 0 \][/tex]
By multiplying through by -1 (to standardize the quadratic inequality):
[tex]\[ x^2 - 15x + 250 \leq 0 \][/tex]

Therefore, the standard form inequality is:
[tex]\[ 25 x^2 + 250 x - 500 \leq 0 \][/tex]

The final answer is:
[tex]\[ 25x^2 + 250x - 500 \leq 0 \][/tex]