Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
We are asked to find a polynomial that has [tex]\(5\)[/tex] as its root. Let's follow the steps to arrive at the correct polynomial equation clearly.
1. Identify the Root and Form the Factor:
- Given that the solution set contains the number [tex]\(5\)[/tex], this means [tex]\(5\)[/tex] is a root of the polynomial.
- Therefore, [tex]\((x - 5)\)[/tex] is a factor of the polynomial.
2. Form a Quadratic Polynomial:
- For simplicity, we can consider the case where the polynomial is of degree 2 (a quadratic polynomial).
- The polynomial can be expressed as the square of the linear factor: [tex]\((x - 5)^2\)[/tex].
3. Expand the Polynomial:
- To expand [tex]\((x - 5)^2\)[/tex], use the binomial expansion formula: [tex]\((a - b)^2 = a^2 - 2ab + b^2\)[/tex].
- Substituting [tex]\(a = x\)[/tex] and [tex]\(b = 5\)[/tex]:
[tex]\[ (x - 5)^2 = x^2 - 2 \cdot x \cdot 5 + 5^2 \][/tex]
- Simplify the expression:
[tex]\[ (x - 5)^2 = x^2 - 10x + 25 \][/tex]
4. Verify the Form:
- We have now found that the expanded form of [tex]\((x - 5)^2\)[/tex] results in the quadratic polynomial:
[tex]\[ x^2 - 10x + 25 \][/tex]
5. Select the Correct Answer:
- Now match the expanded form with the available options:
[tex]\[ \begin{array}{l} x^2 - 5x + 25 = 0 \\ x^2 + 10x + 25 = 0 \\ x^2 - 10x + 25 = 0 \\ x^2 + 5x + 25 = 0 \end{array} \][/tex]
- The polynomial that matches [tex]\(x^2 - 10x + 25\)[/tex] is the correct one.
Thus, the correct polynomial equation for which [tex]\(\{5\}\)[/tex] is the solution set is:
[tex]\[ x^{\wedge} 2-10 x+25 = 0 \][/tex]
1. Identify the Root and Form the Factor:
- Given that the solution set contains the number [tex]\(5\)[/tex], this means [tex]\(5\)[/tex] is a root of the polynomial.
- Therefore, [tex]\((x - 5)\)[/tex] is a factor of the polynomial.
2. Form a Quadratic Polynomial:
- For simplicity, we can consider the case where the polynomial is of degree 2 (a quadratic polynomial).
- The polynomial can be expressed as the square of the linear factor: [tex]\((x - 5)^2\)[/tex].
3. Expand the Polynomial:
- To expand [tex]\((x - 5)^2\)[/tex], use the binomial expansion formula: [tex]\((a - b)^2 = a^2 - 2ab + b^2\)[/tex].
- Substituting [tex]\(a = x\)[/tex] and [tex]\(b = 5\)[/tex]:
[tex]\[ (x - 5)^2 = x^2 - 2 \cdot x \cdot 5 + 5^2 \][/tex]
- Simplify the expression:
[tex]\[ (x - 5)^2 = x^2 - 10x + 25 \][/tex]
4. Verify the Form:
- We have now found that the expanded form of [tex]\((x - 5)^2\)[/tex] results in the quadratic polynomial:
[tex]\[ x^2 - 10x + 25 \][/tex]
5. Select the Correct Answer:
- Now match the expanded form with the available options:
[tex]\[ \begin{array}{l} x^2 - 5x + 25 = 0 \\ x^2 + 10x + 25 = 0 \\ x^2 - 10x + 25 = 0 \\ x^2 + 5x + 25 = 0 \end{array} \][/tex]
- The polynomial that matches [tex]\(x^2 - 10x + 25\)[/tex] is the correct one.
Thus, the correct polynomial equation for which [tex]\(\{5\}\)[/tex] is the solution set is:
[tex]\[ x^{\wedge} 2-10 x+25 = 0 \][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.