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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Match each quadratic equation with its solution set.

Equations:
1. [tex]\( 2x^2 - 8x + 5 = 0 \)[/tex]
2. [tex]\( 2x^2 - 10x - 3 = 0 \)[/tex]
3. [tex]\( 2x^2 - 8x - 3 = 0 \)[/tex]
4. [tex]\( 2x^2 - 9x - 1 = 0 \)[/tex]
5. [tex]\( 2x^2 - 9x + 6 = 0 \)[/tex]

Solution Sets:
A. [tex]\( \frac{9 \pm \sqrt{33}}{4} \)[/tex]
B. [tex]\( \frac{4 \pm \sqrt{89}}{4} \)[/tex]


Sagot :

Let's match each quadratic equation to its corresponding solution set:

1. For the quadratic equation [tex]\(2x^2 - 8x + 5 = 0\)[/tex], the solutions are:
[tex]\[ \left(2 - \frac{\sqrt{6}}{2}, 2 + \frac{\sqrt{6}}{2}\right) \][/tex]

2. For the quadratic equation [tex]\(2x^2 - 10x - 3 = 0\)[/tex], the solutions are:
[tex]\[ \left(\frac{5}{2} - \frac{\sqrt{31}}{2}, \frac{5}{2} + \frac{\sqrt{31}}{2}\right) \][/tex]

3. For the quadratic equation [tex]\(2x^2 - 8x - 3 = 0\)[/tex], the solutions are:
[tex]\[ \left(2 - \frac{\sqrt{22}}{2}, 2 + \frac{\sqrt{22}}{2}\right) \][/tex]

4. For the quadratic equation [tex]\(2x^2 - 9x - 1 = 0\)[/tex], the solutions are:
[tex]\[ \left(\frac{9}{4} - \frac{\sqrt{89}}{4}, \frac{9}{4} + \frac{\sqrt{89}}{4}\right) \][/tex]

5. For the quadratic equation [tex]\(2x^2 - 9x + 6 = 0\)[/tex], the solutions are:
[tex]\[ \left(\frac{9}{4} - \frac{\sqrt{33}}{4}, \frac{9}{4} + \frac{\sqrt{33}}{4}\right) \][/tex]

Matching the equations with their solutions:
- [tex]\(2x^2 - 8x + 5 = 0\)[/tex] matches [tex]\(\left(2 - \frac{\sqrt{6}}{2}, 2 + \frac{\sqrt{6}}{2}\right)\)[/tex]
- [tex]\(2x^2 - 10x - 3 = 0\)[/tex] matches [tex]\(\left(\frac{5}{2} - \frac{\sqrt{31}}{2}, \frac{5}{2} + \frac{\sqrt{31}}{2}\right)\)[/tex]
- [tex]\(2x^2 - 8x - 3 = 0\)[/tex] matches [tex]\(\left(2 - \frac{\sqrt{22}}{2}, 2 + \frac{\sqrt{22}}{2}\right)\)[/tex]
- [tex]\(2x^2 - 9x - 1 = 0\)[/tex] matches [tex]\(\left(\frac{9}{4} - \frac{\sqrt{89}}{4}, \frac{9}{4} + \frac{\sqrt{89}}{4}\right)\)[/tex]
- [tex]\(2x^2 - 9x + 6 = 0\)[/tex] matches [tex]\(\left(\frac{9}{4} - \frac{\sqrt{33}}{4}, \frac{\sqrt{33}}{4} + \frac{9}{4}\right)\)[/tex]

Thus, the pairs are:

1. [tex]\(2x^2 - 8x + 5 = 0\)[/tex] and [tex]\(\left(2 - \frac{\sqrt{6}}{2}, 2 + \frac{\sqrt{6}}{2}\right)\)[/tex]
2. [tex]\(2x^2 - 10x - 3 = 0\)[/tex] and [tex]\(\left(\frac{5}{2} - \frac{\sqrt{31}}{2}, \frac{5}{2} + \frac{\sqrt{31}}{2}\right)\)[/tex]
3. [tex]\(2x^2 - 8x - 3 = 0\)[/tex] and [tex]\(\left(2 - \frac{\sqrt{22}}{2}, 2 + \frac{\sqrt{22}}{2}\right)\)[/tex]
4. [tex]\(2x^2 - 9x - 1 = 0\)[/tex] and [tex]\(\left(\frac{9}{4} - \frac{\sqrt{89}}{4}, \frac{9}{4} + \frac{\sqrt{89}}{4}\right)\)[/tex]
5. [tex]\(2x^2 - 9x + 6 = 0\)[/tex] and [tex]\(\left(\frac{9}{4} - \frac{\sqrt{33}}{4}, \frac{9}{4} + \frac{\sqrt{33}}{4}\right)\)[/tex]

By dragging the corresponding solutions to their equations, you will correctly complete the match.