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Answer:

(a) Simplify:
[tex]\[ \frac{12 t^2}{v} \div \frac{2 t^5}{v^3} \][/tex]

(b) Solve:


Sagot :

Certainly! Let's tackle part (a) and part (b) step-by-step.

### Part (a): Simplify [tex]\(\frac{12 t^2}{v} \div \frac{2 t^5}{v^3}\)[/tex]

To simplify [tex]\(\frac{12 t^2}{v} \div \frac{2 t^5}{v^3}\)[/tex], follow these steps:

1. Rewrite the Division as Multiplication by the Reciprocal:

[tex]\[ \frac{12 t^2}{v} \div \frac{2 t^5}{v^3} = \frac{12 t^2}{v} \times \frac{v^3}{2 t^5} \][/tex]

2. Combine the Fractions:

[tex]\[ \frac{12 t^2 \cdot v^3}{v \cdot 2 t^5} \][/tex]

3. Simplify the Coefficients:

[tex]\[ \frac{12 \cdot v^3}{2 \cdot v} = \frac{12}{2} \cdot \frac{v^3}{v} \][/tex]

[tex]\[ \frac{12}{2} = 6 \][/tex]

4. Simplify the Variable [tex]\(v\)[/tex]:

[tex]\[ \frac{v^3}{v} = v^{3-1} = v^2 \][/tex]

5. Combine [tex]\( t \)[/tex]-Terms:

[tex]\[ \frac{t^2}{t^5} = t^{2-5} = t^{-3} \][/tex]

6. Combine All Simplified Parts:

Putting it all together, we get:

[tex]\[ 6 \cdot v^2 \cdot t^{-3} = 6 v^2 t^{-3} \][/tex]

Thus, the simplified form of [tex]\(\frac{12 t^2}{v} \div \frac{2 t^5}{v^3}\)[/tex] is:

[tex]\[ 6 v^2 t^{-3} \][/tex]

### Part (b): Solve

Since part (b) doesn't provide specific details about what needs to be solved, I'll need more information to proceed accurately. If you have a specific equation or additional context for part (b), please provide it, and I'll be glad to help you solve it. For now, let's conclude part (a) as:

[tex]\[ \boxed{6 v^2 t^{-3}} \][/tex]