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Determine the mass % composition of carbon in 55.4 g C10H14O

Sagot :

hninpapawadisoe09

Answer: 80%

Explanation:

Relative atomic mass of

C - 12    H - 1    O - 16

C - ( 12 x 10 )    H - ( 1 x 14 )    O - 16

total molar mass = 120 + 14 + 16

                            = 150

150 (molar mass) = 55.4g (mass)

total molar mass of carbon = 120

150 = 55.4

120 = x

x = [tex]\frac{(120)(55.4)}{150}[/tex]

  = 44.32g

percentage = [tex]\frac{44.32}{55.4}[/tex]×100

                   = 80%

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