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Compare the speed of two trains, one moving at the speed of 80 km/hr and the other at 10m/sec.

Sagot :

To compare the speeds of the two trains, we need to convert their speeds to the same unit. Here’s the process:

1. **Convert 10 meters per second (m/s) to kilometers per hour (km/h)**:
- 1 m/s = 3.6 km/h.
- Therefore, \( 10 \text{ m/s} = 10 \times 3.6 = 36 \text{ km/h} \).

2. **Compare the speeds**:
- Train A: \( 80 \text{ km/h} \).
- Train B: \( 36 \text{ km/h} \).

**Conclusion**: Train A, moving at 80 km/h, is faster than Train B, which moves at 36 km/h. Specifically, Train A is more than twice as fast as Train B.
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