thewhaleshark
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Question 4: Shown is a cuboid.
(a) Work out the size of angle GEH
(b) Work out the size of angle CHG
(c) Work out the length EG
(d) Work out the size of angle CEG
A
B
F
D
C
4d
3cm
H
7cm

please I'm suffering so hard with this question​

Question 4 Shown Is A Cuboida Work Out The Size Of Angle GEHb Work Out The Size Of Angle CHGc Work Out The Length EGd Work Out The Size Of Angle CEGABFDC4d3cmH7 class=

Sagot :

hninpapawadisoe09

Answer and Step-by-step explanation:

4 a) tan (∠GEH) = [tex]\frac{Opposite}{Adjacent}[/tex]

                          = [tex]\frac{3}{7}[/tex]

∠GEH = [tex]tan^{-1} (\frac{3}{7} )[/tex]

          = 23.2 ( 3 significant figures )

b) tan (∠CHG) = [tex]\frac{Opposite}{Adjacent}[/tex]

                       =[tex]\frac{4}{3}[/tex]

∠CHG = [tex]tan^{-1} (\frac{4}{3})[/tex]

           = 53.1 ( 3 s.f )

c) [tex]EG^{2} = EH^{2} + GH^{2}[/tex]    (pythagoras theorem)

[tex]EG^{2} = 7^{2} +3^{2}[/tex]

EG = [tex]\sqrt{58}[/tex] cm or 7.62 cm ( 3 s.f )

d)  tan (∠CEG) = [tex]\frac{Opposite}{Adjacent}[/tex]

                        = [tex]\frac{4}{\sqrt{58} }[/tex]

∠CEG = [tex]tan^{-1} (\frac{4}{\sqrt{58} } )[/tex]

          = 27.7 ( 3 s.f )

View image hninpapawadisoe09
View image hninpapawadisoe09
View image hninpapawadisoe09
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.