Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To determine which sets of side lengths form a right triangle, we use the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. That is, if [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] are the side lengths of a right triangle with [tex]\(c\)[/tex] being the hypotenuse, then:
[tex]\[a^2 + b^2 = c^2\][/tex]
Let’s analyze each set of side lengths one by one.
### Set 1: [tex]\(3, 14, \sqrt{205}\)[/tex]
- [tex]\(a = 3\)[/tex]
- [tex]\(b = 14\)[/tex]
- [tex]\(c = \sqrt{205}\)[/tex]
Check:
[tex]\[3^2 + 14^2 = 9 + 196 = 205\][/tex]
[tex]\((\sqrt{205})^2 = 205\] Since \(205 = 205\)[/tex], this set of side lengths forms a right triangle.
### Set 2: [tex]\(6, 11, \sqrt{158}\)[/tex]
- [tex]\(a = 6\)[/tex]
- [tex]\(b = 11\)[/tex]
- [tex]\(c = \sqrt{158}\)[/tex]
Check:
[tex]\[6^2 + 11^2 = 36 + 121 = 157\][/tex]
[tex]\((\sqrt{158})^2 = 158\] Since \(157 \neq 158\)[/tex], this set of side lengths does not form a right triangle.
### Set 3: [tex]\(19, 180, 181\)[/tex]
- [tex]\(a = 19\)[/tex]
- [tex]\(b = 180\)[/tex]
- [tex]\(c = 181\)[/tex]
Check:
[tex]\[19^2 + 180^2 = 361 + 32400 = 32761\][/tex]
[tex]\[181^2 = 32761\][/tex]
Since [tex]\(32761 = 32761\)[/tex], this set of side lengths forms a right triangle.
### Set 4: [tex]\(3, 19, \sqrt{380}\)[/tex]
- [tex]\(a = 3\)[/tex]
- [tex]\(b = 19\)[/tex]
- [tex]\(c = \sqrt{380}\)[/tex]
Check:
[tex]\[3^2 + 19^2 = 9 + 361 = 370\][/tex]
[tex]\((\sqrt{380})^2 = 380\] Since \(370 \neq 380\)[/tex], this set of side lengths does not form a right triangle.
### Set 5: [tex]\(2, 9, \sqrt{85}\)[/tex]
- [tex]\(a = 2\)[/tex]
- [tex]\(b = 9\)[/tex]
- [tex]\(c = \sqrt{85}\)[/tex]
Check:
[tex]\[2^2 + 9^2 = 4 + 81 = 85\][/tex]
[tex]\((\sqrt{85})^2 = 85\] Since \(85 = 85\)[/tex], this set of side lengths forms a right triangle.
### Summary
The sets of side lengths that form right triangles are:
- [tex]\(3, 14, \sqrt{205}\)[/tex]
- [tex]\(19, 180, 181\)[/tex]
- [tex]\(2, 9, \sqrt{85}\)[/tex]
[tex]\[a^2 + b^2 = c^2\][/tex]
Let’s analyze each set of side lengths one by one.
### Set 1: [tex]\(3, 14, \sqrt{205}\)[/tex]
- [tex]\(a = 3\)[/tex]
- [tex]\(b = 14\)[/tex]
- [tex]\(c = \sqrt{205}\)[/tex]
Check:
[tex]\[3^2 + 14^2 = 9 + 196 = 205\][/tex]
[tex]\((\sqrt{205})^2 = 205\] Since \(205 = 205\)[/tex], this set of side lengths forms a right triangle.
### Set 2: [tex]\(6, 11, \sqrt{158}\)[/tex]
- [tex]\(a = 6\)[/tex]
- [tex]\(b = 11\)[/tex]
- [tex]\(c = \sqrt{158}\)[/tex]
Check:
[tex]\[6^2 + 11^2 = 36 + 121 = 157\][/tex]
[tex]\((\sqrt{158})^2 = 158\] Since \(157 \neq 158\)[/tex], this set of side lengths does not form a right triangle.
### Set 3: [tex]\(19, 180, 181\)[/tex]
- [tex]\(a = 19\)[/tex]
- [tex]\(b = 180\)[/tex]
- [tex]\(c = 181\)[/tex]
Check:
[tex]\[19^2 + 180^2 = 361 + 32400 = 32761\][/tex]
[tex]\[181^2 = 32761\][/tex]
Since [tex]\(32761 = 32761\)[/tex], this set of side lengths forms a right triangle.
### Set 4: [tex]\(3, 19, \sqrt{380}\)[/tex]
- [tex]\(a = 3\)[/tex]
- [tex]\(b = 19\)[/tex]
- [tex]\(c = \sqrt{380}\)[/tex]
Check:
[tex]\[3^2 + 19^2 = 9 + 361 = 370\][/tex]
[tex]\((\sqrt{380})^2 = 380\] Since \(370 \neq 380\)[/tex], this set of side lengths does not form a right triangle.
### Set 5: [tex]\(2, 9, \sqrt{85}\)[/tex]
- [tex]\(a = 2\)[/tex]
- [tex]\(b = 9\)[/tex]
- [tex]\(c = \sqrt{85}\)[/tex]
Check:
[tex]\[2^2 + 9^2 = 4 + 81 = 85\][/tex]
[tex]\((\sqrt{85})^2 = 85\] Since \(85 = 85\)[/tex], this set of side lengths forms a right triangle.
### Summary
The sets of side lengths that form right triangles are:
- [tex]\(3, 14, \sqrt{205}\)[/tex]
- [tex]\(19, 180, 181\)[/tex]
- [tex]\(2, 9, \sqrt{85}\)[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.