Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To determine which exponential function matches the given table of values, we need to check each function against the [tex]\( (x, f(x)) \)[/tex] pairs provided.
The pairs are:
- [tex]\( (-2, 16) \)[/tex]
- [tex]\( (-1, 8) \)[/tex]
- [tex]\( (0, 4) \)[/tex]
- [tex]\( (1, 2) \)[/tex]
- [tex]\( (2, 1) \)[/tex]
Let's analyze each function one by one to see which one fits the data:
1. [tex]\( f(x) = \frac{1}{2} (4)^x \)[/tex]
- [tex]\( f(-2) = \frac{1}{2} (4)^{-2} = \frac{1}{2} \cdot \frac{1}{16} = \frac{1}{32} \)[/tex] (does not match 16)
- Therefore, function 1 is not the correct function.
2. [tex]\( f(x) = 4 (4)^x \)[/tex]
- [tex]\( f(-2) = 4 (4)^{-2} = 4 \cdot \frac{1}{16} = \frac{1}{4} \)[/tex] (does not match 16)
- Therefore, function 2 is not the correct function.
3. [tex]\( f(x) = 4 \left(\frac{1}{2}\right)^x \)[/tex]
- [tex]\( f(-2) = 4 \left(\frac{1}{2}\right)^{-2} = 4 \cdot 4 = 16 \)[/tex] (matches 16)
- [tex]\( f(-1) = 4 \left(\frac{1}{2}\right)^{-1} = 4 \cdot 2 = 8 \)[/tex] (matches 8)
- [tex]\( f(0) = 4 \left(\frac{1}{2}\right)^x = 4 \cdot 1 = 4 \)[/tex] (matches 4)
- [tex]\( f(1) = 4 \left(\frac{1}{2}\right)^1 = 4 \cdot \frac{1}{2} = 2 \)[/tex] (matches 2)
- [tex]\( f(2) = 4 \left(\frac{1}{2}\right)^2 = 4 \cdot \frac{1}{4} = 1 \)[/tex] (matches 1)
This function matches all the given values in the table.
4. [tex]\( f(x) = \frac{1}{2} \left(\frac{1}{2}\right)^x \)[/tex]
- [tex]\( f(-2) = \frac{1}{2} \left(\frac{1}{2}\right)^{-2} = \frac{1}{2} \cdot 4 = 2 \)[/tex] (does not match 16)
- Therefore, function 4 is not the correct function.
Thus, the exponential function that correctly represents the values in the table is:
[tex]\[ f(x) = 4 \left(\frac{1}{2}\right)^x \][/tex]
The pairs are:
- [tex]\( (-2, 16) \)[/tex]
- [tex]\( (-1, 8) \)[/tex]
- [tex]\( (0, 4) \)[/tex]
- [tex]\( (1, 2) \)[/tex]
- [tex]\( (2, 1) \)[/tex]
Let's analyze each function one by one to see which one fits the data:
1. [tex]\( f(x) = \frac{1}{2} (4)^x \)[/tex]
- [tex]\( f(-2) = \frac{1}{2} (4)^{-2} = \frac{1}{2} \cdot \frac{1}{16} = \frac{1}{32} \)[/tex] (does not match 16)
- Therefore, function 1 is not the correct function.
2. [tex]\( f(x) = 4 (4)^x \)[/tex]
- [tex]\( f(-2) = 4 (4)^{-2} = 4 \cdot \frac{1}{16} = \frac{1}{4} \)[/tex] (does not match 16)
- Therefore, function 2 is not the correct function.
3. [tex]\( f(x) = 4 \left(\frac{1}{2}\right)^x \)[/tex]
- [tex]\( f(-2) = 4 \left(\frac{1}{2}\right)^{-2} = 4 \cdot 4 = 16 \)[/tex] (matches 16)
- [tex]\( f(-1) = 4 \left(\frac{1}{2}\right)^{-1} = 4 \cdot 2 = 8 \)[/tex] (matches 8)
- [tex]\( f(0) = 4 \left(\frac{1}{2}\right)^x = 4 \cdot 1 = 4 \)[/tex] (matches 4)
- [tex]\( f(1) = 4 \left(\frac{1}{2}\right)^1 = 4 \cdot \frac{1}{2} = 2 \)[/tex] (matches 2)
- [tex]\( f(2) = 4 \left(\frac{1}{2}\right)^2 = 4 \cdot \frac{1}{4} = 1 \)[/tex] (matches 1)
This function matches all the given values in the table.
4. [tex]\( f(x) = \frac{1}{2} \left(\frac{1}{2}\right)^x \)[/tex]
- [tex]\( f(-2) = \frac{1}{2} \left(\frac{1}{2}\right)^{-2} = \frac{1}{2} \cdot 4 = 2 \)[/tex] (does not match 16)
- Therefore, function 4 is not the correct function.
Thus, the exponential function that correctly represents the values in the table is:
[tex]\[ f(x) = 4 \left(\frac{1}{2}\right)^x \][/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.