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Solve the following:

[tex]\[ 5 \frac{1}{6} \cdot \left(-\frac{2}{5}\right) = \ \square \][/tex]


Sagot :

To solve [tex]\( 5 \frac{1}{6} \cdot \left( -\frac{2}{5} \right) \)[/tex]:

1. First, we need to convert the mixed number [tex]\( 5 \frac{1}{6} \)[/tex] into an improper fraction.
[tex]\[ 5 \frac{1}{6} = \frac{5 \cdot 6 + 1}{6} = \frac{30 + 1}{6} = \frac{31}{6} \][/tex]

2. Next, we'll multiply this improper fraction by the negative fraction [tex]\(-\frac{2}{5}\)[/tex].
[tex]\[ \frac{31}{6} \cdot \left( -\frac{2}{5} \right) \][/tex]

3. Multiply the numerators together and the denominators together:
[tex]\[ \frac{31 \cdot (-2)}{6 \cdot 5} = \frac{-62}{30} \][/tex]

4. Simplify this fraction by finding the greatest common divisor of 62 and 30. The simplest form of [tex]\(\frac{-62}{30}\)[/tex] is [tex]\(\frac{-31}{15}\)[/tex].

So, the answer to [tex]\( 5 \frac{1}{6} \cdot \left( -\frac{2}{5} \right) \)[/tex] is:
[tex]\[ \frac{-31}{15} \][/tex]