To determine the level of the atmosphere where the rocket will be after one minute, let's break down the problem step-by-step.
1. Time Conversion: Understand that the given time is one minute. Converting this into seconds, since there are 60 seconds in a minute:
[tex]\[
\text{Time} = 1 \, \text{minute} \times 60 \, \text{seconds/minute} = 60 \, \text{seconds}
\][/tex]
2. Rocket Speed: Assume a typical speed of a rocket shortly after launch, which is 7.8 km/s.
3. Distance Calculation: Calculate the distance traveled by the rocket in those 60 seconds.
[tex]\[
\text{Distance} = \text{Speed} \times \text{Time} = 7.8 \, \text{km/s} \times 60\, \text{seconds} = 468 \, \text{km}
\][/tex]
4. Determine the Atmospheric Level: Based on the given altitude ranges in the table, check where 468 km falls:
[tex]\[
\begin{array}{|c|c|}
\text{Stratosphere} & 12-50 \, \text{km} \\
\hline
\text{Mesosphere} & 50-80 \, \text{km} \\
\hline
\text{Thermosphere} & 50-440 \, \text{km} \\
\hline
\text{Exosphere} & > 440 \, \text{km} \\
\hline
\end{array}
\][/tex]
The calculated distance of 468 km exceeds 440 km. Therefore, the rocket is in the Exosphere.
So, the correct answer is:
A. Exosphere
