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Sagot :
To find the slope of the line represented by the equation [tex]\( f(t) = 2t - 6 \)[/tex], we start by identifying the standard form of a linear equation, which is [tex]\( f(t) = mt + b \)[/tex]. Here, [tex]\( m \)[/tex] represents the slope, and [tex]\( b \)[/tex] represents the y-intercept.
Given the equation:
[tex]\[ f(t) = 2t - 6 \][/tex]
We can compare this to the standard form [tex]\( f(t) = mt + b \)[/tex]. By comparison, we see that:
- [tex]\( m = 2 \)[/tex], which is the slope of the line.
- [tex]\( b = -6 \)[/tex], which is the y-intercept of the line.
Therefore, the correct choice from the options provided is:
- The slope is 2 and the [tex]\( y \)[/tex]-intercept is -6.
Thus, the slope of the line represented by the equation [tex]\( f(t) = 2t - 6 \)[/tex] is 2, and the y-intercept is [tex]\( -6 \)[/tex].
Given the equation:
[tex]\[ f(t) = 2t - 6 \][/tex]
We can compare this to the standard form [tex]\( f(t) = mt + b \)[/tex]. By comparison, we see that:
- [tex]\( m = 2 \)[/tex], which is the slope of the line.
- [tex]\( b = -6 \)[/tex], which is the y-intercept of the line.
Therefore, the correct choice from the options provided is:
- The slope is 2 and the [tex]\( y \)[/tex]-intercept is -6.
Thus, the slope of the line represented by the equation [tex]\( f(t) = 2t - 6 \)[/tex] is 2, and the y-intercept is [tex]\( -6 \)[/tex].
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