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Find the distance between two points (2,−1) and (1,−1)

Sagot :

govindsinghdayma1600

Answer

Hence, possible values of ‘a’ are 5 or –3.

Step-by-step explanation:

The distance between two points

P

(

x

1

,

y

1

,

z

1

)

and

Q

(

x

2

,

y

2

,

z

2

)

is given by

P

Q

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

+

(

z

2

−

z

1

)

2

The distance between two points

(

a

,

2

,

1

)

and

(

1

,

–

1

,

1

)

is given as 5.

∴

√

(

a

−

1

)

2

+

(

2

+

1

)

2

+

(

1

−

1

)

2

=

5

⇒

(

a

−

1

)

2

+

9

=

25

⇒

(

a

−

1

)

2

=

16

⇒

a

−

1

=

4

o

r

a

−

1

=

−

4

⇒

(

a

=

5

)

o

r

(a=−3)

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