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What is the slope of the linear relationship shown in this table of values?

[tex]\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
-4 & 11 \\
\hline
2 & -1 \\
\hline
5 & -7 \\
\hline
\end{array}
\][/tex]

A. -3
B. -2
C. 2
D. 3


Sagot :

To find the slope of a linear relationship, you use two points from the table of values and apply the slope formula. The slope [tex]\( m \)[/tex] between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is calculated as follows:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

We can choose any two points from the table. Let's use the points [tex]\((-4, 11)\)[/tex] and [tex]\((2, -1)\)[/tex].

1. Identify the coordinates of the points:
- First point: [tex]\((x_1, y_1) = (-4, 11)\)[/tex]
- Second point: [tex]\((x_2, y_2) = (2, -1)\)[/tex]

2. Substitute the coordinates into the slope formula:

[tex]\[ m = \frac{-1 - 11}{2 - (-4)} \][/tex]

3. Simplify the numerator and the denominator:

[tex]\[ m = \frac{-12}{2 + 4} \][/tex]

4. Simplify further:

[tex]\[ m = \frac{-12}{6} \][/tex]

5. Divide to find the slope:

[tex]\[ m = -2 \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{-2} \][/tex]

So, the slope of the linear relationship shown in the table of values is [tex]\(\boxed{-2}\)[/tex]. The correct answer is B.